28335ADC进不去中断啊，大家看一看什么原因
本帖最后由 halou 于 2015-8-8 20:59 编辑<p>#define ADC_CKPS 0xf // ADC module clock = HSPCLK/2*ADC_CKPS = 25.0MHz/(1*2) = 12.5MHz
#define ADC_SHCLK0xF // S/H width in ADC module periods = 16 ADC clocks
#define AVG 1000// Average sample limit
#define ZOFFSET 0x00// Average Zero offset</p><p>
</p><p>
</p><p><p>InitSysCtrl();</p><p>
EALLOW;
SysCtrlRegs.HISPCP.all = ADC_MODCLK; // HSPCLK = SYSCLKOUT/ADC_MODCLK
EDIS;
InitGpio();
InitCapl();
InitAdc();// For this example, init the ADC
InitEpwm();
PID_init();
// Step 3. Clear all interrupts and initialize PIE vector table:
// Disable CPU interrupts
DINT;
InitPieCtrl();
// Disable CPU interrupts and clear all CPU interrupt flags:
IER = 0x0000;
IFR = 0x0000;</p><p>
InitPieVectTable();
EALLOW;// This is needed to write to EALLOW protected registers
//PieVectTable. ECAP1_INT = &ISRCap1;
//PieVectTable. ECAP2_INT = &ISRCap2;
//PieVectTable. ECAP3_INT = &ISRCap1;
//PieVectTable.TINT0 = &ISRTimer0;
PieVectTable.ADCINT = &adc_isr;
//PieVectTable.XINT13 = &cpu_timer1_isr;
//PieVectTable.TINT2 = &cpu_timer2_isr;
EDIS;
IER |= M_INT1; // Enable CPU Interrupt 1
PieCtrlRegs.PIEIER1.bit.INTx6 = 1; //ADCINT</p><p>
// Enable global Interrupts and higher priority real-time debug events:
EINT; // Enable Global interrupt INTM
ERTM; // Enable Global realtime interrupt DBGM</p><p>
////////////////////////////////////////////////////////////////////////</p><p><div class="blockcode"><blockquote><p></p><p>void InitAdc(void)
{
extern void DSP28x_usDelay(Uint32 Count);</p><p>
EALLOW;
SysCtrlRegs.PCLKCR0.bit.ADCENCLK = 1;
ADC_cal();
EDIS
AdcRegs.ADCTRL3.all = 0x00E0;// Power up bandgap/reference/ADC circuits
DELAY_US(ADC_usDELAY); // Delay before converting ADC channels
AdcRegs.ADCTRL1.bit.ACQ_PS = ADC_SHCLK;// Sequential mode: Sample rate = 1/[(2+ACQ_PS)*ADC clock in ns]
// = 1/(3*40ns) =8.3MHz (for 150 MHz SYSCLKOUT)
// = 1/(3*80ns) =4.17MHz (for 100 MHz SYSCLKOUT)
// If Simultaneous mode enabled: Sample rate = 1/[(3+ACQ_PS)*ADC clock in ns]
AdcRegs.ADCTRL3.bit.ADCCLKPS = ADC_CKPS; </p><p>//AdcRegs.ADCTRL1.bit.CPS=1; //内核时钟预定标器，1为二分频</p><p> AdcRegs.ADCTRL1.bit.SEQ_CASC = 1; // 1Cascaded mode级联模式
AdcRegs.ADCCHSELSEQ1.bit.CONV00 = 0x0; // Setup ADCINA0 as 1st SEQ1 conv.</p><p>
//AdcRegs.ADCST.bit.INT_SEQ1_CLR=1;
//AdcRegs.ADCST.bit.INT_SEQ2_CLR=1;</p><p> AdcRegs.ADCTRL1.bit.CONT_RUN = 1; // Setup continuous run
AdcRegs.ADCTRL1.bit.SEQ_OVRD = 0; // Enable Sequencer override feature
// Initialize all ADC channel selects to A0
AdcRegs.ADCCHSELSEQ1.all = 0x0;
AdcRegs.ADCCHSELSEQ2.all = 0x0;
AdcRegs.ADCCHSELSEQ3.all = 0x0;
AdcRegs.ADCCHSELSEQ4.all = 0x0;</p><p> // AdcRegs.ADCTRL3.bit.SMODE_SEL = 1; //0-顺序采样，1-同步采样
AdcRegs.ADCMAXCONV.all = 0x0000; // Setup ADA0 conv's on SEQ1
</p><p> AdcRegs.ADCTRL2.bit.INT_ENA_SEQ1 = 1;
AdcRegs.ADCTRL2.bit.RST_SEQ1 = 1;
AdcRegs.ADCTRL2.bit.SOC_SEQ1 = 1;
}
interrupt void adc_isr(void)
{
while (AdcRegs.ADCST.bit.INT_SEQ1 == 0){}</p><p>AdcA = ((AdcRegs.ADCRESULT0)>>4);
Adc_isrTimes++;</p><p> if(Adc_isrTimes==1000)
{
Adc_isrTimes = 0;
}
// Clear INT flag for this timer
AdcRegs.ADCTRL2.bit.RST_SEQ1 = 1; // Reset SEQ1
AdcRegs.ADCST.bit.INT_SEQ1_CLR = 1; // Clear INT SEQ1 bit
PieCtrlRegs.PIEACK.all = PIEACK_GROUP1; // Acknowledge interrupt to PIE</p><p> return;
}</p></p></p>
这是主程序中的测试代码</p><p> if(AdcRegs.ADCST.bit.SEQ1_BSY ==1)
flagintadc2 =1;
if(AdcRegs.ADCST.bit.INT_SEQ1 ==1)
flagintadc =1;</p><p>
</p><p>程序执行后
</p>
中断最后加个 AdcRegs.ADCTRL2.bit.SOC_SEQ1 = 1;试试 楼主解决了吗？遇到了同样的问题 HYTERIA 发表于 2017-7-7 16:44
楼主解决了吗？遇到了同样的问题
哥们解决了吗？
页:
[1]