实现LED点阵左右移动的程序

只看该作者 · 2015-8-16 20:53

#include<reg52.h>

#define uchar unsigned char

unsigned char code tab[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};//定义扫描列

unsigned char code digittab[]={

 

0x00,0x00,0x00,0x00,0x00,0x00,0x3e,0x41,0x41,0x41,0x3e,0x00, //0

 

0x00,0x00,0x00,0x00,0x21,0x7f,0x01,0x00, //1

 

0x00,0x00,0x27,0x45,0x45,0x45,0x39,0x00, //2

 

0x00,0x00,0x22,0x49,0x49,0x49,0x36,0x00, //3

 

0x00,0x00,0x0c,0x14,0x24,0x7f,0x04,0x00, //4

 

0x00,0x00,0x72,0x51,0x51,0x51,0x4e,0x00, //5

 

0x00,0x00,0x3e,0x49,0x49,0x49,0x26,0x00, //6

 

0x00,0x00,0x40,0x40,0x40,0x4f,0x70,0x00, //7

 

0x00,0x00,0x36,0x49,0x49,0x49,0x36,0x00, //8

 

0x00,0x00,0x32,0x49,0x49,0x49,0x3e,0x00, //9

 

0x00,0x00,0x7F,0x48,0x48,0x30,0x00,0x00, //P

 

0x00,0x00,0x7F,0x48,0x4C,0x73,0x00,0x00, //R

 

0x00,0x00,0x7F,0x49,0x49,0x49,0x00,0x00, //E

 

0x00,0x00,0x3E,0x41,0x41,0x62,0x00,0x00, //C

 

0x00,0x00,0x7F,0x08,0x08,0x7F,0x00,0x00, //H

 

0x00,0x00,0x00,0xFF,0xFF,0x00,0x00,0x00, //I

 

0x00,0x7F,0x10,0x08,0x04,0x7F,0x00,0x00, //N

 

0x7C,0x48,0x48,0xFF,0x48,0x48,0x7C,0x00, 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 //中

 

};//要显示的字符

 

void delay(int t)

{

 int i;

 for(i=1;i<=t;i++);

}//延时函数

void main(void)

{

 int a,b,c;

 while(1)

 {

  for(a=0;a<144;a++)  //所有要显示的列数

  {

   

    for(b=0;b<50;b++)//控制移动速度

    {

    P2=0xfe;      ///最右边的列先显示，程序定义向左移动

    for(c=0;c<8;c++)//稍加修改可以变成向右移动

    {                //例中P2接LED点阵阳极，P0接阴极

     P0=digittab[a+c];//同时显示8列

     delay(100);

     P0=0x00;   //禁止扫描列变换时，其它列亮！

     P2=P2<<1|P2>>7;

    

     }

     }

    

  }