函数调用不了？怎么回事呢

只看该作者 · 2015-9-9 22:45

本帖最后由慧剑温情于 2015-9-10 17:57 编辑

以下是函数全部，函数void Thekeyadd()在主函数里调用不起，但是把void Thekeyadd()函数内容直接写到主函数里就能正常运行，怎么回事啊？？附带能正常运行图片
#include<reg52.h>
sbit keyout4=P2^0;
sbit key=P2^6;
unsigned char code ledchar[]={
      0xC0, 0xF9, 0xA4, 0xB0, 0x99, 0x92, 0x82, 0xF8,
0x80, 0x90, 0x88, 0x83, 0xC6, 0xA1, 0x86, 0x8E
      };
unsigned char ge=0;
unsigned char shi=0;
void delay();
void Thekeyadd();
void main()
{

      keyout4=0;
      P1=0x08;
      P0=0xff;
      EA=1;
      TMOD=0X01;
      TH0=0XFC;
      TL0=0X67;
      ET0=1;
      TR0=1;

      while(1)
      {

            Thekeyadd();
      }
}
void delay()
{
      unsigned int shu=1000;
      while(shu)
      {
            shu--;
      }
}
void Thekeyadd()
{
      unsigned char sec=0;
      unsigned kbuff;
      bit backup=1;
      ge=sec%10;
      shi=sec/10%10;
      kbuff=key;
      if(kbuff!=backup)
      {
            delay();
            if(kbuff==key)
            {
                     if(backup==0)
                     {
                              sec++;
                              if(sec>=100)
                              {
                                    sec=0;
                              }

                     }
                     backup=kbuff;
            }
      }
}
void interrupttimer0() interrupt 1
{
      static unsigned char i=0;
      TH0=0XFC;
      TL0=0X67;
      P0=0XFF;
      switch(i)
      {
            case 0:P1=0X08;i++;P0=ledchar[ge];break;
            case 1:P1=0X09;i=0;P0=ledchar[shi];break;
            default :break;
      }
}