F28335的adc转换

只看该作者 · 2015-12-18 15:05

大家帮我看一下为什么我的ADC结果寄存器的值为0呢，但是实际测得时候肯定有值，下边为我的程序：
#include "DSP2833x_Project.h"    // Device Headerfile and Examples Include File
interrupt void adc_isr(void);
void adc_init(void);
Uint16 LoopCount;
Uint16 ConversionCount;
Uint16 Voltage1;
Uint16 Voltage2;
Uint16 A;
void main()
{
InitSysCtrl();
EALLOW;
#if (CPU_FRQ_150MHZ)    // Default - 150 MHz SYSCLKOUT
   #define ADC_MODCLK 0x3 // HSPCLK = SYSCLKOUT/2*ADC_MODCLK2 = 150/(2*3) = 25.0 MHz
#endif
#if (CPU_FRQ_100MHZ)
   #define ADC_MODCLK 0x2 // HSPCLK = SYSCLKOUT/2*ADC_MODCLK2 = 100/(2*2) = 25.0 MHz
#endif
EDIS;
DINT;
InitPieCtrl();
IER = 0x0000;
IFR = 0x0000;
InitPieVectTable();
EALLOW;  // This is needed to write to EALLOW protected register
PieVectTable.ADCINT = &adc_isr;
EDIS; // This is needed to disable write to EALLOW protected registers



PieCtrlRegs.PIEIER1.bit.INTx6 = 1;
IER |= M_INT1; // Enable CPU Interrupt 1
EINT;       // Enable Global interrupt INTM
ERTM;       // Enable Global realtime interrupt DBGM
LoopCount = 0;
ConversionCount = 0;
A=0;
Voltage1=0;
Voltage2=0;

adc_init();  // For this example, init the ADC
  AdcRegs.ADCTRL2.bit.SOC_SEQ1 = 1;//启动一次转换过程

// Wait for ADC interrupt
for(;;)
{
   LoopCount++;
}

}

void adc_init(void)
{
  InitAdc();
EALLOW;
SysCtrlRegs.HISPCP.all = ADC_MODCLK;  // HSPCLK = SYSCLKOUT/ADC_MODCLK
EDIS;


AdcRegs.ADCTRL3.bit.ADCCLKPS = 0;    //核心时钟分频（不分频）
AdcRegs.ADCTRL1.bit.CPS = 1; //进行2分频，则ADCCLK=HSPCLK=12.5MHZ
AdcRegs.ADCTRL1.bit.ACQ_PS = 2;       //采样窗口，即采样时间为3个1/12.5M=240ns

//工作模式设置
AdcRegs.ADCTRL1.bit.SEQ_CASC = 1;       //级联模式
AdcRegs.ADCTRL3.bit.SMODE_SEL = 0;       //顺序采样
AdcRegs.ADCMAXCONV.all = 1;          //2路信号


AdcRegs.ADCCHSELSEQ1.bit.CONV00=0x8; //转换通道为ADCINB0
AdcRegs.ADCCHSELSEQ1.bit.CONV01=0x9; //转换通道为ADCINB1

AdcRegs.ADCTRL1.bit.CONT_RUN = 0; //启动/停止模式
//AdcRegs.ADCTRL1.bit.SEQ_OVRD = 0; //允许完成MAX_CONV1+1次后回绕

//使能中断且设置启动转换ADC方式

AdcRegs.ADCTRL2.bit.INT_ENA_SEQ1 = 1;  // Enable SEQ1 interrupt (every EOS)
AdcRegs.ADCTRL2.bit.INT_MOD_SEQ1 = 0;  //INT_SEQ1的中断在每次SEQ1序列结束时被置位

}

interrupt void  adc_isr(void)
{

  Voltage1 = AdcRegs.ADCRESULT0 >>4;
  Voltage2= AdcRegs.ADCRESULT1 >>4;

A=A+1;
  // Reinitialize for next ADC sequence
  AdcRegs.ADCTRL2.bit.RST_SEQ1 = 1;       // Reset SEQ1
  AdcRegs.ADCST.bit.INT_SEQ1_CLR = 1;    // Clear INT SEQ1 bit

  PieCtrlRegs.PIEACK.all = PIEACK_GROUP1; // Acknowledge interrupt to PIE
  AdcRegs.ADCTRL2.bit.SOC_SEQ1 = 1;//启动一次转换过程
  //return;
}