LPC2368的UART2、UART3与UART0、UART1有什么区别？

只看该作者 · 2007-3-28 13:33

同样的处理方法UART0、UART1正常，UART2、UART3死机，下面是那段程序：
#include <LPC23xx.h>
#define CR     0x0D
void Delay(unsigned int cnt)
{
    do
    {
        cnt--;
    }
    while(cnt!=0);
}
int sendchar0 (int ch)
{
  if (ch == '\n')  {
    while (!(U0LSR & 0x20));
    U0THR = CR;                          /* output CR */
  }
  while (!(U0LSR & 0x20));
  return (U0THR = ch);
}
int sendchar1 (int ch)
{
  if (ch == '\n')  {
    while (!(U1LSR & 0x20));
    U1THR = CR;                          /* output CR */
  }
  while (!(U1LSR & 0x20));
  return (U1THR = ch);
}
int sendchar2 (int ch)
{
  if (ch == '\n')  {
    while (!(U2LSR & 0x20));
    U2THR = CR;                          /* output CR */
  }
  while (!(U2LSR & 0x20));
  return (U2THR = ch);
}

int sendchar3 (int ch)
{
  if (ch == '\n')  {
    while (!(U3LSR & 0x20));
    U3THR = CR;                          /* output CR */
  }
  while (!(U3LSR & 0x20));
  return (U3THR = ch);
}main()
{
    PINSEL0 |= 0x00000050;               // Enable TxD0 and RxD0
    PINSEL4 |= 0x0000000A;               // Enable RxD1 and TXD0
    PINSEL0 |= 0x00500000;                 // Enable TXD2 and RXD2
    PINSEL9 |= 0x0F000000;                 // Enable TXD3 and RXD3
    PINSEL10 = 0;

  U0FDR    = 0;
  U0LCR    = 0x83;
  U0DLL    = 16;
  U0DLM    = 0;
  U0LCR    = 0x03;

  U1FDR    = 0;
  U1LCR    = 0x83;
  U1DLL    = 16;
  U1DLM    = 0;
  U1LCR    = 0x03;

  U2FDR    = 0;
  U2LCR    = 0x83;
  U2DLL    = 16;
  U2DLM    = 0;
  U2LCR    = 0x03;

  U3FDR    = 0;
  U3LCR    = 0x83;
  U3DLL    = 16;
  U3DLM    = 0;
  U3LCR    = 0x03;
  while(1)
  {
      sendchar0(0x55);
      sendchar1(0x55);
      sendchar3(0x55);
      Delay(10000);
  }
}