基于LPC2148的按键KEY与LCD与蜂鸣结合

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楼主

冷玄冰之泪|

楼主 | 2009-11-11 11:11 | 只看该作者回帖奖励

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LCD, LPC2148, CONFIG, include, LED

//按键按下，对应的LED灯亮，并且蜂鸣器鸣叫，按键松开，全部停止

#include "config.h"
const uint32 BEEP = (1<<7);
const uint32 KEY1 = (1<<21);
const uint32 KEY2 = (1<<22);
const uint32 KEY3 = (1<<29);
const uint32 KEY4 = (1<<30);
const uint32 LEDS4 = (0x0F << 16); // P1[19:16]控制LED4~LED1
void DelayNS(uint32 dly)
{
uint32 i;

for( ; dly>0; dly--)
  for(i=0; i<50000; i++);
}
int main (void)
{
PINSEL0 = 0x00000000;    //设置管脚连接GPIO
PINSEL1 = 0x00000000;
IO1DIR = LEDS4;    //设置LED控制口为输出
IO0DIR = BEEP;    //设置BEEP口为输出

while(1)
{
  IO0SET = BEEP;    //关闭蜂鸣器

  if((IO0PIN&KEY1) == 0) //当KEY1按下，LED1亮，并且蜂鸣器鸣叫
  {
IO1CLR = LEDS4 & (1 << 16);
IO0CLR = BEEP;
DelayNS(25);
IO0SET = BEEP;
  }
  else IO1SET = LEDS4 & (1 << 16);

  if((IO0PIN&KEY2) == 0) //当KEY2按下，LED2亮，并且蜂鸣器鸣叫
  {
IO1CLR = LEDS4 & (1 << 17);
IO0CLR = BEEP;
DelayNS(25);
IO0SET = BEEP;
  }
  else IO1SET = LEDS4 & (1 << 17);

  if((IO0PIN&KEY3) == 0) //当KEY3按下，LED3亮，并且蜂鸣器鸣叫
  {
IO1CLR = LEDS4 & (1 << 18);
IO0CLR = BEEP;
DelayNS(25);
IO0SET = BEEP;
  }
  else IO1SET = LEDS4 & (1 << 18);

  if((IO0PIN&KEY4) == 0) //当KEY4按下，LED4亮，并且蜂鸣器鸣叫
  {
IO1CLR = LEDS4 & (1 << 19);
IO0CLR = BEEP;
DelayNS(25);
IO0SET = BEEP;
  }
  else IO1SET = LEDS4 & (1 << 19);
}

return 0;
}

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