cs5513数字滤波，有时候AD值突然下跌。。

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anbin1985| 中级技术员

楼主 | 2009-11-23 16:00 | 只看该作者回帖奖励

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AD, 数字滤波, dc, ADC, TE

利用16位AD做数字滤波，取20个AD的平均值。在中断里面取AD值。滤波次数太多的话，大于10次，AD就会出现下跌情况。例如采样值计算后为60.00，有时候会突然变为58.xx.请高手研究下这个程序。。
oid get_Padc_count()
{
unsigned char i;
CONA=1;CONB=0;
delay(2);
PPP=0;
fit=fit-1;
switch(fit)
{
case 19:{filter1[19]=ADConv();};break;
case 18:{filter1[18]=ADConv();};break;
case 17:{filter1[17]=ADConv();};break;
case 16:{filter1[16]=ADConv();};break;
case 15:{filter1[15]=ADConv();};break;
case 14:{filter1[14]=ADConv();};break;
case 13:{filter1[13]=ADConv();};break;
case 12:{filter1[12]=ADConv();};break;
case 11:{filter1[11]=ADConv();};break;
case 10:{filter1[10]=ADConv();};break;
case 9:{filter1[9]=ADConv();};break;
case 8:{filter1[8]=ADConv();};break;
case 7:{filter1[7]=ADConv();};break;
case 6:{filter1[6]=ADConv();};break;
case 5:{filter1[5]=ADConv();};break;
case 4:{filter1[4]=ADConv();};break;
case 3:{filter1[3]=ADConv();};break;
case 2:{filter1[2]=ADConv();};break;
case 1:{filter1[1]=ADConv();};break;
case 0:{filter1[0]=ADConv();fit=fit3;};break;
default:break;
}
   for(i=0;i<fit3;i++)
  {PPP=PPP+filter1[i]; }
   PPP=PPP/fit3;

}

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