请帮忙看下着程序各位大虾^^

只看该作者 · 2010-9-14 15:21

大家帮忙看下这个程序，P1口接数码管，4位动态显示，P0接矩阵键盘，4x3键盘，当我按下键盘时候，没有松开，数码管显示只有最后一位显示（保持的），松开才显示新的数，这是怎么回事呐？？
#include<reg52.h>
#include<intrins.h>
#define uint unsigned int
#define uchar unsigned char
void delayms(uchar);
void display(uchar dat);
uchar keyscan();
sbit LS138A=P2^2;
sbit LS138B=P2^3;
sbit LS138C=P2^4;
uchar code dis[] = { 0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0XD8,0x80,0x90,
                              0x88,0x83,0xc6,0xa1,0x86,0x8e,0x89,0x86,0xc7,0xff};
uchar temp,num,wel[8];
void main()
{
  while(1)
  {
  display(keyscan());
  }
}
void delayms(uchar ms)
{
  uchar i;
  while(ms--)
for(i=0;i<125;i++);
}
uchar keyscan()
{
  P0=0xfd;
temp=P0;
temp=temp&0xf1;
while(temp!=0xf1)
{
delayms(5);
temp=P0;
temp=temp&0xf1;
while(temp!=0xf1)
{
temp=P0;
switch(temp)
{
   case 0xed:num=1; break;
   case 0xdd:num=2; break;
   case 0xbd:num=3; break;
   case 0x7d:num=4; break;
}
while(temp!=0xf1)
   {
   temp=P0;
   temp=temp&0xf1;
   }
}
}

  P0=0xfb;
temp=P0;
temp=temp&0xf1;
while(temp!=0xf1)
{
  delayms(5);
  temp=P0;
   temp=temp&0xf1;
  while(temp!=0xf1)
  {
   temp=P0;
   switch(temp)
   {
   case 0xeb:num=5; break;
case 0xdb:num=6; break;
case 0xbb:num=7; break;
case 0x7b:num=8; break;
   }
   while(temp!=0xf1)
   {
   temp=P0;
   temp=temp&0xf1;
   }
  }

}
  P0=0xf7;
  temp=P0;
  temp=temp&0xf1;
while(temp!=0xf1)
{
  delayms(5);
  temp=P0;
   temp=temp&0xf1;
  while(temp!=0xf1)
  {
   temp=P0;
   switch(temp)
   {
   case 0xe7:num=9; break;
case 0xd7:num=10; break;
case 0xb7:num=11; break;
case 0x77:num=12; break;
   }
   while(temp!=0xf1)
   {
   temp=P0;
   temp=temp&0xf1;
   }
  }

}
return num;
}
void display(uchar dat)
{
uchar j;
wel[0]=dis[dat];
wel[1]=dis[dat];
wel[2]=dis[dat];
wel[3]=dis[dat];
wel[4]=dis[dat];
wel[5]=dis[dat];
wel[6]=dis[dat];
wel[7]=dis[dat];
for(j=0;j<8;j++)
{
  P1=wel[j];
  switch(j)
  {

      case 0:LS138A=0; LS138B=0; LS138C=0; break;
      case 1:LS138A=1; LS138B=0; LS138C=0; break;
      case 2:LS138A=0; LS138B=1; LS138C=0; break;
      case 3:LS138A=1; LS138B=1; LS138C=0; break;
      case 4:LS138A=0; LS138B=0; LS138C=1; break;
      case 5:LS138A=1; LS138B=0; LS138C=1; break;
      case 6:LS138A=0; LS138B=1; LS138C=1; break;
      case 7:LS138A=1; LS138B=1; LS138C=1; break;
  }
  delayms(1);
}
}

只看该作者 · 2010-9-14 15:31

while(temp!=0xf1)
   {
   temp=P0;
   temp=temp&0xf1;
   }
~~1234~~

   while(temp!=0xf1)
   {
   temp=P0;
   temp=temp&0xf1;
   }
~~~5678~~~

   while(temp!=0xf1)
   {
   temp=P0;
   temp=temp&0xf1;
   }
~~~9 10 11 12~~
当按下键时，程序会在这三个地方的其中其中一个停止~~数码管只会显示出最后扫描的那个数