用N76E003写switch case语句发现一个问题，求各位前辈解答！

只看该作者 · 2018-1-10 15:36

先附上一段代码
#define N 2
void fun(void)
{
  static u8 sta=0;
  switch(sta)
  {
case 0:
   list1_on(1);list2_on(1);list3_on(3);
   delay(N);
sta++;
break;
case 1:
   list1_on(2);list2_on(2);list3_on(4);
   delay(N);
sta++;
break;
case 2:
   list1_on(1);list2_on(3);list3_on(1);
   delay(N);
sta++;
break;
case 3:
   list1_on(3);list2_on(4);list3_on(2);
   delay(N);
sta++;
break;
case 4:
   list1_on(2);list2_on(1);list3_on(3);
   delay(N);
sta++;
break;
case 5:
   list1_on(3);list2_on(2);list3_on(4);
   delay(N);
sta++;
break;
case 6:
   list1_on(2);list2_on(3);list3_on(2);
   delay(N);
sta++;
break;
case 7:
   list1_on(3);list2_on(1);list3_on(3);
   delay(N);
sta++;
break;
case 8:
   list1_on(4);list2_on(2);list3_on(1);
   delay(N);
sta++;
break;
case 9:
   list1_on(5);list2_on(3);list3_on(2);
   delay(N);
sta++;
break;
case 10:
   list1_on(1);list2_on(4);list3_on(1);
   delay(N);
sta++;
break;
case 11:
   list1_on(2);list2_on(2);list3_on(2);
   delay(N);
sta++;
break;
case 12:
   list1_on(3);list2_on(1);list3_on(3);
   delay(N);
sta++;
break;
case 13:
   list1_on(2);list2_on(2);list3_on(4);
   delay(N);
sta++;
break;
case 14:
   list1_on(1);list2_on(3);list3_on(5);
   delay(N);
sta++;
break;
case 15:
   list1_on(2);list2_on(4);list3_on(6);
   delay(N);
sta++;
break;
case 16:
   list1_on(1);list2_on(1);list3_on(1);
   delay(N);
sta++;
break;
case 17:
   list1_on(3);list2_on(2);list3_on(2);
   delay(N);
sta++;
break;
case 18:
   list1_on(2);list2_on(1);list3_on(3);
   delay(N);
sta++;
break;
case 19:
   list1_on(4);list2_on(2);list3_on(4);
   delay(N);
sta++;
break;
case 20:
   list1_on(2);list2_on(3);list3_on(2);
   delay(N);
sta++;
break;
case 21:
   list1_on(3);list2_on(1);list3_on(3);
   delay(N);
sta++;
break;
case 22:
   list1_on(4);list2_on(2);list3_on(4);
   delay(N);
sta++;
break;
case 23:
   list1_on(5);list2_on(3);list3_on(1);
   delay(N);
sta++;
break;
case 24:
   list1_on(6);list2_on(4);list3_on(2);
   delay(N);
sta++;
break;
case 25:
   list1_on(1);list2_on(5);list3_on(3);
   delay(N);
sta++;
break;
case 26:
   list1_on(2);list2_on(6);list3_on(4);
   delay(N);
sta++;
break;
case 27:
   list1_on(3);list2_on(2);list3_on(1);
   delay(N);
sta++;
break;
case 28:
   list1_on(1);list2_on(3);list3_on(2);
   delay(N);
sta++;
break;
case 29:
   list1_on(2);list2_on(1);list3_on(3);
   delay(N);
sta++;
break;
case 30:
   list1_on(3);list2_on(2);list3_on(4);
   delay(N);
sta++;
break;
default:
   sta = 0;
break;

  }
}
上面的代码是sta从0到30反复执行，delay是软件延时函数。
现在调试的时候发现一个问题，如图