复杂pwm波的生成方法

只看该作者 · 2018-6-27 19:56

请问28335怎么生成一个复杂的pwm波？
它的高低电平情况是：
1111000 1111000 1111000 1111000 1111000 1111000 1111000 0001111 0001111 0001111 0001111 0001111 0001111 0001111

只看该作者 · 2018-6-27 20:35

加个变频的代码

只看该作者 · 2018-6-27 21:34

ePWM模块，看你需要哪种调制方式，都能输出啊

只看该作者 · 2018-6-27 21:47

变换这么多次也能用pwm模块吗

只看该作者 · 2018-6-27 21:59

不是只有zro prd cmpa cmpb可以用来动作吗？

只看该作者 · 2018-6-27 22:27

是在pwm模块定时中断里面加吗？

只看该作者 · 2018-6-27 22:39

interrupt void epwm3_timer_isr(void)
{
      EPwm3TimerIntCount++;
switch(EPwm3Regs.CMPA.half.CMPA)
{
      case 1435:
                  EPwm3Regs.CMPA.half.CMPA=3348;
      break;

      case 3348:
            EPwm3Regs.CMPA.half.CMPA=4783;
      break;

      case 4783:
            EPwm3Regs.CMPA.half.CMPA=6696;
      break;

      case 6696:
            EPwm3Regs.CMPA.half.CMPA=8131;
      break;

      case 8131:
            EPwm3Regs.CMPA.half.CMPA=10044;
      break;

      case 10044:
                  EPwm3Regs.CMPA.half.CMPA=11479;
      break;

      case 11479:
            EPwm3Regs.CMPA.half.CMPA=13392;
      break;

      case 13392:
                  EPwm3Regs.CMPA.half.CMPA=14827;
      break;

      case 14827:
            EPwm3Regs.CMPA.half.CMPA=16740;
      break;

      case 16740:
            EPwm3Regs.CMPA.half.CMPA=18175;
      break;

      case 18175:
            EPwm3Regs.CMPA.half.CMPA=20088;
      break;

      case 20088:
            EPwm3Regs.CMPA.half.CMPA=21522;
      break;

      case 21522:
                  EPwm3Regs.CMPA.half.CMPA=25349;
      break;

      case 25349:
            EPwm3Regs.CMPA.half.CMPA=26783;
      break;

      case 26783:
                  EPwm3Regs.CMPA.half.CMPA=28697;
      break;

      case 28697:
            EPwm3Regs.CMPA.half.CMPA=30131;
      break;

      case 30131:
            EPwm3Regs.CMPA.half.CMPA=32045;
      break;

      case 32045:
            EPwm3Regs.CMPA.half.CMPA=33479;
      break;

      case 33479:
            EPwm3Regs.CMPA.half.CMPA=35392;
      break;

      case 35392:
                  EPwm3Regs.CMPA.half.CMPA=36827;
      break;

      case 36827:
            EPwm3Regs.CMPA.half.CMPA=38740;
      break;

      case 38740:
            EPwm3Regs.CMPA.half.CMPA=40175;
      break;

      case 40175:
            EPwm3Regs.CMPA.half.CMPA=42088;
      break;

      case 42088:
            EPwm3Regs.CMPA.half.CMPA=43523;
      break;

case 43523:
         EPwm3Regs.CMPA.half.CMPA=45436;
      break;

      case 45436:
            EPwm3Regs.CMPA.half.CMPA=1435;
      break;

         default:
         break;
}
EPwm3Regs.ETCLR.bit.INT = 1;
PieCtrlRegs.PIEACK.all = PIEACK_GROUP3;
}

只看该作者 · 2018-6-27 22:56

EPwm3Regs.AQCTLA.bit.ZRO=AQ_SET;
EPwm3Regs.AQCTLA.bit.CAU=AQ_TOGGLE;
EPwm3Regs.ETSEL.bit.INTSEL = ET_CTRU_CMPA;
EPwm3Regs.ETSEL.bit.INTEN = PWM3_INT_ENABLE;
EPwm3Regs.ETPS.bit.INTPRD = ET_1ST;

这是我pwmsetup里的  是增计数模式

2万 · 2018-6-27 23:20

给一个合适的比较表吧

复杂pwm波的生成方法

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