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题目：求1+2!+3!+...+20!的和。 程序分析：此程序只是把累加变成了累乘。 方法一- #!/usr/bin/python
- # -*- coding: UTF-8 -*-
-
- n = 0
- s = 0
- t = 1
- for n in range(1,21):
- t *= n
- s += t
- print ('1! + 2! + 3! + ... + 20! = %d' % s)
- #!/usr/bin/python
- # -*- coding: UTF-8 -*-
-
- s = 0
- l = range(1,21)
- def op(x):
- r = 1
- for i in range(1,x + 1):
- r *= i
- return r
- s = sum(map(op,l))
- print ('1! + 2! + 3! + ... + 20! = %d' % s)
1! + 2! + 3! + ... + 20! = 2561327494111820313
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楼主
