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题目：求1+2!+3!+...+20!的和。 程序分析：此程序只是把累加变成了累乘。 方法一#!/usr/bin/python
# -*- coding: UTF-8 -*-
n = 0
s = 0
t = 1
for n in range(1,21):
t *= n
s += t
print ('1! + 2! + 3! + ... + 20! = %d' % s)
#!/usr/bin/python
# -*- coding: UTF-8 -*-
s = 0
l = range(1,21)
def op(x):
r = 1
for i in range(1,x + 1):
r *= i
return r
s = sum(map(op,l))
print ('1! + 2! + 3! + ... + 20! = %d' % s)
1! + 2! + 3! + ... + 20! = 2561327494111820313
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