2440裸奔初级问题，求教啦

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zjgtan|

楼主 | 2012-3-9 14:21 | 只看该作者回帖奖励

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gp, unsigned, TI, LED, DM

我第一次裸奔2440，一个简单的程序。以下是源程序
init.s
AREA |DATA|,CODE,READONLY
ENTRY
ldr r13, = 0x1000
IMPORT LedMain
b LedMain
END

main.c
#define GPFCON (*(volatile unsigned *)0x56000050);
#define GPFDAT (*(volatile unsigned *)0x56000054);
#define GPFUP (*(volatile unsigned *)0x56000058);
void delay(unsigned int x);
int LedMain()
{
unsigned char ledtab[] = {0xdf, 0xbf, 0x7f};
int i;
GPFUP &= 0xffffff1f;
//报错：(serious)c2304e: <command> expected but found '&='
GPFCON &= 0xffff0000;
//报错：(serious)c2304e: <command> expected but found '&='
GPFCON |= 0x5400;
//报错：(serious)c2304e: <command> expected but found '|='

while (1)
{
  for (i = 0; i < 3; ++i)
  {
GPFDAT = ledtab[i];
delay(10);
  }
}

return 0;
}
void delay(unsigned int x)
{ //简单的延迟函数
unsigned int i, j, k;
for (i = 0; i <= x; ++i)
{
  for (j = 0; j < 0xff; ++j)
  {
for (k = 0; k < 0xff; ++k);
  }
}

}

实在搞不清这是为什么，求教啦

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