新手求助！STM32F407中断无法实现

只看该作者 · 2021-7-25 15:40

本人刚入门STM32F4系列（开发板为STM32F407VET6），在学习中断这一章节的时候出现了些问题.
拟设计代码实现功能：使用中断完成按下按键后led灯由点亮转向熄灭
问题：编写完成代码后无法实现该功能

开发板部分原理图如下：（“LED指示灯”和“用户按键”）
设置按下K1按键（PE3）后，D3的LED灯熄灭（PA6）

以下为个人编写代码，可能会有不规范的地方，望见谅
#include "stm32f4xx.h"
#define PAout(n) *(volatile uint32_t *)(0x42000000 + (GPIOF_BASE + 0x14 - 0x40000000)*32 + n*4)

static GPIO_InitTypeDef GPIO_InitStructure;
static EXTI_InitTypeDef EXTI_InitStructure;
static NVIC_InitTypeDef NVIC_InitStructure;

int main(void){
//led灯PA6;
RCC_AHB1PeriphClockCmd(RCC_AHB1Periph_GPIOA, ENABLE);
GPIO_InitStructure.GPIO_Mode = GPIO_Mode_OUT;
GPIO_InitStructure.GPIO_Pin = GPIO_Pin_6;
GPIO_InitStructure.GPIO_Speed = GPIO_Speed_100MHz;
GPIO_InitStructure.GPIO_OType = GPIO_OType_PP;
GPIO_InitStructure.GPIO_PuPd = GPIO_PuPd_NOPULL;
GPIO_Init(GPIOA, &GPIO_InitStructure);

//按键PE3;
RCC_AHB1PeriphClockCmd(RCC_AHB1Periph_GPIOE, ENABLE);
GPIO_InitStructure.GPIO_Mode = GPIO_Mode_IN;
GPIO_InitStructure.GPIO_Pin = GPIO_Pin_3;
GPIO_InitStructure.GPIO_PuPd = GPIO_PuPd_UP;
GPIO_InitStructure.GPIO_Speed = GPIO_Speed_100MHz;
GPIO_Init(GPIOE, &GPIO_InitStructure);

//外部中断;
SYSCFG_EXTILineConfig(EXTI_PortSourceGPIOE, EXTI_PinSource3);
EXTI_InitStructure.EXTI_Line = EXTI_Line3;
EXTI_InitStructure.EXTI_Mode = EXTI_Mode_Interrupt;
EXTI_InitStructure.EXTI_Trigger = EXTI_Trigger_Falling;
EXTI_InitStructure.EXTI_LineCmd = ENABLE;
EXTI_Init(&EXTI_InitStructure);

NVIC_InitStructure.NVIC_IRQChannel = EXTI3_IRQn;
NVIC_InitStructure.NVIC_IRQChannelPreemptionPriority = 0x0F;
NVIC_InitStructure.NVIC_IRQChannelSubPriority = 0x0F;
NVIC_InitStructure.NVIC_IRQChannelCmd = ENABLE;
NVIC_Init(&NVIC_InitStructure);

while(1){
PAout(6) = 0;
}

}
//设置中断函数;
void EXTI3_IRQHandler(void){
if(EXTI_GetITStatus(EXTI_Line3) == SET){
PAout(6) = 1;
}
EXTI_ClearITPendingBit(EXTI_Line3);
}

恳请大佬帮忙分析解决（已被困扰一天）
谢谢！！！