急求！！编译阶段出现下面错误expression must have(pointer-to-)funct

只看该作者 · 2014-4-6 11:55

RT，代码及错误如下，实在是找不出是什么错误，请各位大神帮忙看看，先谢谢大家了！
代码中蓝色字体对应的分别是line26,line27，line28和line29
"mfcc.c", line 26: error: expression must have (pointer-to-) function type
"mfcc.c", line 26: error: expression must have (pointer-to-) function type
"mfcc.c", line 27: error: expression must have (pointer-to-) function type
"mfcc.c", line 27: error: expression must have (pointer-to-) function type
"mfcc.c", line 27: error: expression must have (pointer-to-) function type
"mfcc.c", line 28: error: expression must have (pointer-to-) function type
"mfcc.c", line 28: error: expression must have (pointer-to-) function type
"mfcc.c", line 29: error: expression must have (pointer-to-) function type
"mfcc.c", line 29: error: expression must have (pointer-to-) function type
"mfcc.c", line 29: error: expression must have (pointer-to-) function type

#include"math.h"
#include"constants.h"
void mfcc(double mfcc[][N],double S[][N],int frmN)       //S is the enframed matrix  (frmlen*frmN)
{
  int i,j,k;
  double f[M+2];
  double W[frmlen][M];
  double temp[N][frmlen];
  double cof[N][M];
  double sum=0;
  double melf,x1;

  melf=2595*log10(1+fs/700);

  for(i=0;i<M+2;i++)
  {
f=700*pow(10,(melf*i/(2595*(M+1))-1));
  }
  for(i=0;i<M;i++)
  {
for(j=0;j<frmlen;j++)
{
   x1=j*fs/frmlen;
   if((x1 >= f(i)) && (x1 <= f(i+1)))
      W[j]=(x1-f(i))/(f(i+1)-f(i));
   else if((x1 >= f(i+1)) && (x1 <= f(i+2)))
      W[j]=(f(i+2)-x1)/(f(i+2)-f(i+1));
   else
      W[j]=0;
}
  }                      //W is a frmlen*M matrix

  for(i=0;i<frmlen;i++)
  {
for(j=0;j<N;j++)
{
   temp[j]=pow(S[j],2);
}
  }

  for(i=0;i<N;i++)
  {
for(k=0;k<M;k++)
{
   sum=0;
   for(j=0;j<frmlen;j++)
   {
      sum=sum+temp[j]*W[j][k];
   }
   cof[k]=sum;
}
  }

  for(i=0;i<frmN;i++)
  {
for(j=0;j<M;j++)
{
   sum=0;
   for(k=0;k<M;k++)
   {
      sum=sum+log10(cof[k])*cos((k-0.5)*j*PI/M);
   }
   mfcc[j]=sum;
}
}
  for(i=0;i<M;i++)
  {
for(j=0;j<N;j++)
{
   if(j<(frmN-1))
   {
      if(i<(M-1))
      mfcc[j]=mfcc[j+1];
else
      mfcc[j]=0;
   }
   else
{
   mfcc[j]=0;       /*effective mfcc is (M-1)*frmN *;from frmN+1 column to N column is 0 */
}
  }
}
}

只看该作者 · 2014-4-6 14:45

f=700*pow(10,(melf*i/(2595*(M+1))-1));问题应该在这一句，f是数组首地址，复制时候应该强制类型转换为指针形式加上（double *）

2万 · 2014-4-6 23:25

你调用此函数void mfcc(double mfcc[][N],double S[][N],int frmN) 的代码贴出来吧
我觉得应该是函数传递的参数问题吧

只看该作者 · 2014-4-7 08:59

zhangmangui 发表于 2014-4-6 23:25
你调用此函数void mfcc(double mfcc[][N],double S[][N],int frmN) 的代码贴出来吧
我觉得应该是函数传递的 ...

double temp_data[frmlen][N];
double Mfcc_data[M][N];
temp_frmN=floor((len-1-frmlen)/frmcnt)+1; % temp_frmN根据这个表达式求得
下面就是对mfcc()函数的调用
mfcc(Mfcc_data,temp_data,temp_frmN);