关于两板28335——CAN通讯的问题

只看该作者 · 2014-6-4 11:43

现有两板28335A（主控板）、B（采集、算法板），需要进行CAN通讯数据传输。

要求：
1、开始，数据初始化要求A→B传输；
2、数据初始化完毕，要求B采集数据→A传输。

问题：
现在偶尔出现两板不能联调的情况，这时两板程序均停留在：
while(ECanbRegs.CANTA.all !=0x00000001)

个人觉得是因为两板发送、接收的程序时序设置不合理。

大家有什么宝贵意见，关于两板均要求收发在进行设置有什么特别要注意的吗？

只看该作者 · 2014-6-4 16:14

请问你那有CAN的接收程序吗？

2万 · 2014-6-7 01:21

DSP28335编程总结（详细的CAN总线说明）

2万 · 2014-6-7 01:22

caowei0516 发表于 2014-6-4 16:14
请问你那有CAN的接收程序吗？

DSP28335资料分享

只看该作者 · 2014-6-10 10:34

zhangmangui 发表于 2014-6-7 01:22
DSP28335资料分享

#include "DSP2833x_Device.h"    // DSP2833x Headerfile Include File
#include "DSP2833x_Examples.h" // DSP2833x Examples Include File

  interrupt void ECAN0INTB_ISR(void);
  Uint32 Rec_l0;
  Uint32 Rec_h0;

void main(void)
{
struct ECAN_REGS ECanbShadow;

InitSysCtrl();

InitECanGpio();

DINT;

InitPieCtrl();

IER = 0x0000;
IFR = 0x0000;

EALLOW;
PieVectTable.ECAN0INTB = &ECAN0INTB_ISR;    // TIMER0断向重定位
EDIS;

EALLOW;
ECanbShadow.CANTIOC.all = ECanbRegs.CANTIOC.all;
ECanbShadow.CANTIOC.bit.TXFUNC = 1;
ECanbRegs.CANTIOC.all = ECanbShadow.CANTIOC.all;

ECanbShadow.CANRIOC.all = ECanbRegs.CANRIOC.all;
ECanbShadow.CANRIOC.bit.RXFUNC = 1;
ECanbRegs.CANRIOC.all = ECanbShadow.CANRIOC.all;
EDIS;

ECanbRegs.CANME.all = 0;

ECanbMboxes.MBOX16.MSGID.all = 0x9555AAA0;

ECanbRegs.CANMD.all = 0xFFFF0000;

ECanbRegs.CANME.all = 0xFFFFFFFF;

ECanbMboxes.MBOX16.MSGCTRL.bit.DLC = 8;

ECanbMboxes.MBOX16.MSGCTRL.bit.RTR = 0;

EALLOW;
ECanbRegs.CANMIM.all = 0xFFFFFFFF;
ECanbShadow.CANMC.all = ECanbRegs.CANMC.all;
ECanbShadow.CANMC.bit.CCR = 1;
ECanbRegs.CANMC.all = ECanbShadow.CANMC.all;
EDIS;

do
{
   ECanbShadow.CANES.all = ECanbRegs.CANES.all;
} while(ECanbShadow.CANES.bit.CCE != 1 );

EALLOW;
ECanbShadow.CANBTC.all = ECanbRegs.CANBTC.all;

ECanbShadow.CANBTC.bit.BRPREG = 9; // (BRPREG + 1) = 10 feeds a 15 MHz CAN clock
ECanbShadow.CANBTC.bit.TSEG2REG = 5 ; // to the CAN module. (150 / 10 = 15)
ECanbShadow.CANBTC.bit.TSEG1REG = 7;  // Bit time = 15
ECanbRegs.CANBTC.all = ECanbShadow.CANBTC.all;

ECanbShadow.CANMC.all = ECanbRegs.CANMC.all;
ECanbShadow.CANMC.bit.CCR = 0;
ECanbRegs.CANMC.all = ECanbShadow.CANMC.all;
EDIS;

do
{
   ECanbShadow.CANES.all = ECanbRegs.CANES.all;
} while(ECanbShadow.CANES.bit.CCE != 0 );

EALLOW;
ECanbShadow.CANMC.all = ECanbRegs.CANMC.all;
ECanbShadow.CANMC.bit.STM = 0; // Configure CAN for self-test mode
ECanbShadow.CANMC.bit.SCB = 1; // eCAN mode (reqd to access 32 mailboxes)
ECanbRegs.CANMC.all = ECanbShadow.CANMC.all;
EDIS;

EALLOW;
ECanaRegs.CANMIM.all = 0xFFFFFFFF;    //邮箱中断屏蔽位
ECanaRegs.CANMIL.all = 0;          //邮箱中断将产生在ECAN0INT
ECanaRegs.CANGIF0.all = 0xFFFFFFFF;  //全局中断标志寄存器
ECanaRegs.CANGIM.bit.I0EN = 1; //ECAN0INT中断请求线被使能
EDIS;

PieCtrlRegs.PIEIER9.bit.INTx7 = 1; //使能PIE中断
IER |= M_INT9;                      //使能CPU中断
EINT;
ERTM;

for(;;)
{

}
}


// Begin receiving

interrupt void ECAN0INTB_ISR(void)  // eCAN-B
{
while(ECanbRegs.CANRMP.all != 0x00010000 ) {}  // Wait for all TAn bits to be set..
   ECanbRegs.CANRMP.all = 0x00010000; // Clear all TAn
   Rec_l0 =  ECanbMboxes.MBOX16.MDL.all;
   Rec_h0 =  ECanbMboxes.MBOX16.MDH.all;
   PieCtrlRegs.PIEACK.bit.ACK9 = 1;
   ECanbRegs.CANOPC.all = 0;
   EINT;

}

能帮我看看这个接收为什么进入不了中断吗？

2万 · 2014-6-10 13:45

caowei0516 发表于 2014-6-10 10:34
#include "DSP2833x_Device.h" // DSP2833x Headerfile Include File
#include "DSP2833x_Examples.h ...

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