LPC1768串口UART2的485发送正常，接收进不了中断

只看该作者 · 2014-8-14 22:31

本帖最后由香莲清风于 2014-8-20 21:32 编辑

void Uart2Init(void)
{
uint16_t usFdiv;
LPC_GPIO1->FIODIR |= ((unsigned int)1 << 31);
LPC_GPIO1->FIOPIN &=  ~((unsigned int)1<<31);                /* 485_DIR = 0 */
LPC_PINCON->PINSEL0 |= (((unsigned int)1<<20)|((unsigned int)1<<22));
LPC_SC->PCONP |= (1<<24);
usFdiv = (FPCLK / 16) / 2400;
LPC_UART2->DLM  = usFdiv / 256;
LPC_UART2->DLL  = usFdiv % 256;

LPC_UART2->LCR  = 0x1b;
LPC_UART2->FCR  = 0x07;
LPC_UART2->IER  = 0x01;
NVIC_EnableIRQ(UART2_IRQn);             /* enable irq in nvic             */
}

void Uart2SendByte(int8_t buf)
{
      LPC_UART2->THR = buf;
      while (!(LPC_UART2->LSR & 0x20));
}

void uart2SendStr (uint8_t *pucStr, uint32_t ulNum)
{
uint32_t i;
LPC_GPIO1->FIOCLR |= ((unsigned int)1 << 31);
Delay(5);
for (i = 0; i < ulNum; i++)
{
      Uart2SendByte (*pucStr++);
}
Delay(5);
LPC_GPIO1->FIOSET |=  ((unsigned int)1 << 31);
}

void UART2_IRQHandler(void)
{
while ((LPC_UART2->IIR & 0x01) == 0)
{
   switch (LPC_UART2->IIR & 0x0E)
   {
      case 0x04:
               for (GulNum = 0; GulNum < 8; GulNum++)
               {
               GucRcvBuf[GulNum+RcvLen] = LPC_UART2->RBR;
            }
            break;
      case 0x0C:
         while ((LPC_UART2->LSR & 0x01) == 0x01)
         {
            GucRcvBuf[RcvLen] = LPC_UART2->RBR;
      }
      break;
      default:
            break;
      }
}
}
这是程序部分，不知道有没有大侠遇到过呀

只看该作者 · 2014-8-14 22:36

刚发错版块了，不知道有没有人遇到过，求教啊，搞了好几天了

LPC1768串口UART2的485发送正常，接收进不了中断

相关下载

相关帖子