请教M0串口问题？

只看该作者 · 2015-1-3 15:28

麻烦各位高手帮忙解决各串口问题。
M0控制器FIFO触发级别配置为接收8个字节产生中断，通过PC上的串口调试助手发送一串数据，如01，02 ,03,04一直到0F.。但是进入中断服务程序后接受寄存器接受的第一个字节却为0F. 变成0F,02,03,04---0F..
望高手帮忙解答下，谢了。

只看该作者 · 2015-1-4 08:51

把你的UART初始化部分代码和中断处理部分贴出来，不然大家没办法替你解答

1万 · 2015-1-4 08:53

你先设定一个应答信号，当应答完成后再发送你的数据，不然一直发送应答信号。

只看该作者 · 2015-1-5 10:14

void UART0_Init(void)
{
P3_MFP = (P3_MFP & (~(P31_TXD0 | P30_RXD0))) | (TXD0 | RXD0); //ÅäÖÃP3.1ºÍP3.0ÎªUART¹¦ÄÜ
P3_PMD &=~(3);
   P3_PMD &=(~(1<<3));
IPRSTC2 |= UART0_RST;                         //¸´Î»UARTÄ£¿é
IPRSTC2 &= ~UART0_RST;                         //UARTÄ£¿é´Ó¸´Î»×´Ì¬»Ö¸´µ½Õý³£¹¤×÷×´Ì¬

APBCLK |= UART0_CLKEN;                         //Ê¹ÄÜUARTÊ±ÖÓ
CLKSEL1 = (CLKSEL1 & (~UART_CLK)) | UART_12M;    //Ñ¡ÔñÍâ²¿12M×÷ÎªUARTÊ±ÖÓÔ´
CLKDIV &= ~(15<<8);                            //ÉèÖÃUARTÊ±ÖÓ³ýÆµÖµÎª0

UA0_FCR |= TX_RST;                            //¸´Î»·¢ËÍFIFO
UA0_FCR |= RX_RST;                            //¸´Î»½ÓÊÕFIFO
   UA0_FCR |=(1<<5);                               //ÖÐ¶Ï´¥·¢¼¶±ð

UA0_LCR &= ~PBE;                               //Ð£ÑéÎ»½ûÖ¹
UA0_LCR = (UA0_LCR & (~WLS)) | WL_8BIT;       //Êý¾Ý¿í¶ÈÎª8Î»
UA0_LCR &= NSB_ONE;                            //1Î»Í£Ö¹Î»

UA0_BAUD |= DIV_X_EN;                         //Ä£Ê½2:DIV_X_EN = 1
UA0_BAUD |= DIV_X_ONE;                         //Ä£Ê½2:DIV_X_ONE =1

UA0_BAUD |= ((12000000 / 9600) - 2);          //ÉèÖÃ²¨ÌØÂÊÎª9600£¬Ä£Ê½2²¨ÌØÂÊ=UART_CLK/(UA_BAUD+2)
// NVIC_IPR3 |=(1<<6);       //ÖÐ¶ÏÓÅÏÈ¼¶ÅäÖÃ
UA0_TOR =(UA0_TOR &(~0x3F))|(40);
UA0_IER |=TIME_OUT_EN;    //Ê¹ÄÜ½ÓÊÕ³¬Ê±¼ÆÊýÆ÷
UA0_IER |=RTO_IEN;
UA0_IER |= RDA_IEN;                            //Ê¹ÄÜÖÐ¶Ï
NVIC_ISER = UART0_INT;                         //Ê¹ÄÜNVIC UART0ÖÐ¶Ï
}

只看该作者 · 2015-1-5 10:21

void UART0_IRQHandler(void)
{
uint8_t i,x=0;
count =0;
//  SYST_CSR &=~1;
if(UA0_ISR &TOUT_INT)
{
  UA0_FCR |= RX_RST;
  UA0_FCR |= TX_RST;
}
if(UA0_ISR & RDA_INT)
{
   for(i=8;i<16;i++)
  {
while (UA0_FSR & RX_EMPTY);             //µÈ×Ö·û
  command[i] =UA0_RBR;
if(command[8]!=0xEE)
{
command[i-8] =command[i];
   x =command[2];
}
else
{
x =command[2];
}
  }
if((x==2)||(x==12)||(x==14)||(x==16)||(x==18))
  {
if(command[8]==0xee)
{
UA0_FCR |= RX_RST;
UA0_FCR |= TX_RST;
   recive_flag =0xAA;
switch_flag =0x55;
command[8] =0;
}
else if((command[3]==0)&&(command[2]!=2))
{
UA0_FCR |= RX_RST;
UA0_FCR |= TX_RST;
   recive_flag =0xAA;
switch_flag =0x55;
}
  }
  else if(x<21)
  {
UA0_FCR |= RX_RST;
UA0_FCR |= TX_RST;
recive_flag =0xAA;
switch_flag =0x55;
command[8] =0;
  }
else
{
SYST_CVR =0;
SYST_CSR |=1;       //Ê¹ÄÜSysTickÊ±ÖÓ
  }
}
}