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题目：输入某年某月某日，判断这一天是这一年的第几天？ 程序分析：以3月5日为例，应该先把前两个月的加起来，然后再加上5天即本年的第几天，特殊情况，闰年且输入月份大于2时需考虑多加一天： 程序源代码： - #!/usr/bin/python3
-
- year = int(input('year:\n'))
- month = int(input('month:\n'))
- day = int(input('day:\n'))
-
- months = (0,31,59,90,120,151,181,212,243,273,304,334)
- if 0 < month <= 12:
- sum = months[month - 1]
- else:
- print ('data error')
- sum += day
- leap = 0
- if (year % 400 == 0) or ((year % 4 == 0) and (year % 100 != 0)):
- leap = 1
- if (leap == 1) and (month > 2):
- sum += 1
- print ('it is the %dth day.' % sum)
结果： - year:
- 2015
- month:
- 6
- day:
- 7
- it is the 158th day.
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