F28335的程序不能在flash中运行
问: 28335的程序不能在flash中运行 问者: 1065105320f28335我编写的程序在ram中运行没有问题。 在flash中不能运行。我学习了你们的帮助文档，下载了你们的在flash中运行的实例，发现可以在flash中运行。我讲实例稍微修改，只修改了bss和ebss部分从l4ram改为外部存储器extmem0，发现程序下载后能正常运行，但是将cpu复位后运行就不对了。。如果问题解决，请回邮件到huangpeng8@163.com.谢谢。问: 回复: 28335的程序不能在flash中运行 问者: 1065105我用的是F28335_example_BIOS_flash.pjt项目文件
问: 回复: 28335的程序不能在flash中运行 问者: 1065105我将我的电机控制程序按例子做了修改，发现相同的问题，就是下载到flash后能运行正常，但是断电再运行，就不正常了。如果这是接上调试器运行，发现能运行到main函数，但是不能运行到我定义的各个进程。
问: 回复: 28335的程序不能在flash中运行 问者: 1099911.请确认你的boot 模式是否设置为Flash模式，即需要设置有关boot的GPIO的状态。2. 你的外部存储器extmem0是指什么地址？
问: 回复: 28335的程序不能在flash中运行 问者: 1065105最后发现问题和外部ram无关。只要关电源再开机，机器都会运行都FXN_F_selfLoop函数而死机。问题还是没有解决
答: 回复: 28335的程序不能在flash中运行 问者: 1357265您好！请在Code Start Branch.asm中，将XINTF引脚配置成XINTF，因为默认是GPIO。再尝试一下。具体的可以参考下面的代码：***********************************************************************WD_DISABLE .set 1 ;set to 1 to disable WD, else set to 0 .ref _c_int00 .global code_start .ref _InitSysCtrl;开外设.ref _xintf_zone6and7_timing;初始化XINTF总线为16BIT(用户的系统硬件设计相关)************************************************************************ Function: codestart section** Description: Branch to code starting point*********************************************************************** .sect "codestart"code_start: .if WD_DISABLE == 1 LB wd_disable ;Branch to watchdog disable code .else LB _c_int00 ;Branch to start of boot.asm in RTS library .endif;end codestart section************************************************************************ Function: wd_disable** Description: Disables the watchdog timer*********************************************************************** .if WD_DISABLE == 1 .textwd_disable: SETC OBJMODE ;Set OBJMODE for 28x object code EALLOW ;Enable EALLOW protected register access MOVZ DP, #7029h>>6;Set data page for WDCR register MOV @7029h, #0068h;Set WDDIS bit in WDCR to disable WD EDISLCR _InitSysCtrlLCR _xintf_zone6and7_timing ;Disable EALLOW protected register access LB _c_int00 ;Branch to start of boot.asm in RTS library .endif;end wd_disable.end
问: 回复: 28335的程序不能在flash中运行 问者: 1065105谢谢， extmem0 地址：0x100000，len：0x30000.void UserInit(void){#ifdef EXAMPLE_FLASH // EXAMPLE_FLASH, if defined, is in CCS project options// Section .trcdata is generated by DSP/BIOS.// It must be copied from its load to its run address BEFORE main().memcpy(&trcdata_runstart, &trcdata_loadstart, &trcdata_loadend - &trcdata_loadstart);#endif//--- CPU InitializationInitSysCtrl(); // Initialize the CPUInitPieCtrl(); // Initialize and enable the PIEInitWatchdog(); // Initialize the Watchdog TimerInitGpio(); // Initialize the shared GPIO pinsInitXintf();。。。void InitXintf(void){EALLOW;XintfRegs.XINTCNF2.bit.XTIMCLK = 1;// write bufferingwhile(XintfRegs.XINTCNF2.bit.WLEVEL != 0); // poll the WLEVEL bit;XintfRegs.XINTCNF2.bit.WRBUFF = 3;// XCLKOUT is disabledXintfRegs.XINTCNF2.bit.CLKOFF = 1;// XCLKOUT = XTIMCLKXintfRegs.XINTCNF2.bit.CLKMODE = 0;SysCtrlRegs.PCLKCR3.bit.DMAENCLK = 1; // DMA ClockSysCtrlRegs.PCLKCR3.bit.XINTFENCLK = 1; // XTIMCLKSysCtrlRegs.PCLKCR3.bit.GPIOINENCLK = 1; // GPIO input clock//all Zone read/write lead/active/trail timingXintfRegs.XTIMING0.bit.X2TIMING = 1;//0;//1;// Zone 0------------------------------------。。。 // Zone will not sample XREADY signalXintfRegs.XTIMING0.bit.USEREADY = 0;// XintfRegs.XTIMING0.bit.READYMODE = 1;// sample asynchronous// Size must be either:// 0,1 = x32 or// 1,1 = x16 other values are reservedXintfRegs.XTIMING0.bit.XSIZE = 3;// Zone 6------------------------------------// When using ready, ACTIVE must be 1 or greater// Lead must always be 1 or greater// Zone write timingXintfRegs.XTIMING6.bit.XWRLEAD = 1;//3;XintfRegs.XTIMING6.bit.XWRACTIVE =1 ;//7;XintfRegs.XTIMING6.bit.XWRTRAIL = 0;//3;// Zone read timingXintfRegs.XTIMING6.bit.XRDLEAD = 1;//3;XintfRegs.XTIMING6.bit.XRDACTIVE = 1;//7;XintfRegs.XTIMING6.bit.XRDTRAIL = 0;//3;// single all Zone read/write lead/active/trail timingXintfRegs.XTIMING6.bit.X2TIMING = 0;// Zone will sample XREADY signalXintfRegs.XTIMING6.bit.USEREADY = 0;// 1;// XintfRegs.XTIMING6.bit.READYMODE = 1;// sample asynchronous// Size must be either:// 0,1 = x32 or// 1,1 = x16 other values are reserved#if DATA_WIDTH >16XintfRegs.XTIMING6.bit.XSIZE = 1;#elseXintfRegs.XTIMING6.bit.XSIZE = 3;#endif// Bank switching// Assume Zone 6 is slow, so add additional BCYC cycles// when ever switching from Zone 6 to another Zone.// This will help avoid bus contention.XintfRegs.XBANK.bit.BANK = 6;XintfRegs.XBANK.bit.BCYC = 6;// double all Zone read/write lead/active/trail timingXintfRegs.XTIMING7.bit.X2TIMING = 1;// Zone will sample XREADY signalXintfRegs.XTIMING7.bit.USEREADY = 1;XintfRegs.XTIMING7.bit.READYMODE = 1;// sample asynchronous// Size must be either:// 0,1 = x32 or// 1,1 = x16 other values are reservedXintfRegs.XTIMING7.bit.XSIZE = 3;// Bank switching// Assume Zone 7 is slow, so add additional BCYC cycles// when ever switching from Zone 6 to another Zone.// This will help avoid bus contention.// XintfRegs.XBANK.bit.BANK = 7;// XintfRegs.XBANK.bit.BCYC = 7;//EDIS;//Force a pipeline flush to ensure that the write to//the last register configured occurs before returning. //EALLOW; // InitXintf16Gpio();//EALLOW; GpioCtrlRegs.GPCMUX1.bit.GPIO64 = 3;// XD15 GpioCtrlRegs.GPCMUX1.bit.GPIO65 = 3;// XD14 GpioCtrlRegs.GPCMUX1.bit.GPIO66 = 3;// XD13 GpioCtrlRegs.GPCMUX1.bit.GPIO67 = 3;// XD12 GpioCtrlRegs.GPCMUX1.bit.GPIO68 = 3;// XD11 GpioCtrlRegs.GPCMUX1.bit.GPIO69 = 3;// XD10 GpioCtrlRegs.GPCMUX1.bit.GPIO70 = 3;// XD19 GpioCtrlRegs.GPCMUX1.bit.GPIO71 = 3;// XD8 GpioCtrlRegs.GPCMUX1.bit.GPIO72 = 3;// XD7 GpioCtrlRegs.GPCMUX1.bit.GPIO73 = 3;// XD6 GpioCtrlRegs.GPCMUX1.bit.GPIO74 = 3;// XD5 GpioCtrlRegs.GPCMUX1.bit.GPIO75 = 3;// XD4 GpioCtrlRegs.GPCMUX1.bit.GPIO76 = 3;// XD3 GpioCtrlRegs.GPCMUX1.bit.GPIO77 = 3;// XD2 GpioCtrlRegs.GPCMUX1.bit.GPIO78 = 3;// XD1 GpioCtrlRegs.GPCMUX1.bit.GPIO79 = 3;// XD0 GpioCtrlRegs.GPBMUX1.bit.GPIO40 = 3;// XA0/XWE1n GpioCtrlRegs.GPBMUX1.bit.GPIO41 = 3;// XA1 GpioCtrlRegs.GPBMUX1.bit.GPIO42 = 3;// XA2 GpioCtrlRegs.GPBMUX1.bit.GPIO43 = 3;// XA3 GpioCtrlRegs.GPBMUX1.bit.GPIO44 = 3;// XA4 GpioCtrlRegs.GPBMUX1.bit.GPIO45 = 3;// XA5 GpioCtrlRegs.GPBMUX1.bit.GPIO46 = 3;// XA6 GpioCtrlRegs.GPBMUX1.bit.GPIO47 = 3;// XA7 GpioCtrlRegs.GPCMUX2.bit.GPIO80 = 3;// XA8 GpioCtrlRegs.GPCMUX2.bit.GPIO81 = 3;// XA9 GpioCtrlRegs.GPCMUX2.bit.GPIO82 = 3;// XA10 GpioCtrlRegs.GPCMUX2.bit.GPIO83 = 3;// XA11 GpioCtrlRegs.GPCMUX2.bit.GPIO84 = 3;// XA12 GpioCtrlRegs.GPCMUX2.bit.GPIO85 = 3;// XA13 GpioCtrlRegs.GPCMUX2.bit.GPIO86 = 3;// XA14 GpioCtrlRegs.GPCMUX2.bit.GPIO87 = 3;// XA15 GpioCtrlRegs.GPBMUX1.bit.GPIO39 = 3;// XA16 GpioCtrlRegs.GPAMUX2.bit.GPIO31 = 3;// XA17 GpioCtrlRegs.GPAMUX2.bit.GPIO30 = 3;// XA18 GpioCtrlRegs.GPAMUX2.bit.GPIO29 = 3;// XA19//GpioCtrlRegs.GPBMUX1.bit.GPIO34 = 3;// XREADY// GpioCtrlRegs.GPBMUX1.bit.GPIO35 = 3;// XRNW// GpioCtrlRegs.GPBMUX1.bit.GPIO38 = 3;// XWE0GpioCtrlRegs.GPBMUX1.bit.GPIO34 = 0;// XREADYGpioCtrlRegs.GPBMUX1.bit.GPIO35 = 0;// XRNW GpioCtrlRegs.GPBMUX1.bit.GPIO38 = 3;// XWE0 GpioCtrlRegs.GPBMUX1.bit.GPIO36 = 3;// XZCS0 GpioCtrlRegs.GPBMUX1.bit.GPIO37 = 3;// XZCS7 GpioCtrlRegs.GPAMUX2.bit.GPIO28 = 3;// XZCS6 EDIS;asm(" RPT #7 || NOP");} // end of InitXintf()问题没有解决。
答: 回复: 28335的程序不能在flash中运行 答者: 1357265关于上电复位，请参考TI的标准的复位电路，有些电源芯片本身就包含复位信号输出，例如TPS767D318。如果用阻容电路，要保证复位信号保持512个Cycle的低电平，再拉高。
答: 回复: 28335的程序不能在flash中运行 答者: 1065105按照陈先生的提示，问题基本解决。现在还剩下的问题是上电复位有时行有时不行。估计和复位电路有关。感谢陈先生，感谢各位给我的帮助。
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