图中a/(s+b)是什么补偿呀?既不是一阶超前,又不是滞后,也不是P

Calculating&nbsp;the&nbsp;Compensator&nbsp;Coefficients<br />A&nbsp;convenient&nbsp;way&nbsp;of&nbsp;determining&nbsp;the&nbsp;coefficients&nbsp;for&nbsp;an<br />IIR&nbsp;(Infinite&nbsp;Impulse&nbsp;Response)&nbsp;compensator&nbsp;from&nbsp;an<br />analog&nbsp;transfer&nbsp;function&nbsp;in&nbsp;the&nbsp;Laplace&nbsp;(s)&nbsp;domain&nbsp;is&nbsp;the<br />Bilinear&nbsp;z-transform.&nbsp;The&nbsp;following&nbsp;example&nbsp;illustrates<br />the&nbsp;technique&nbsp;for&nbsp;a&nbsp;compensator&nbsp;with&nbsp;a&nbsp;single&nbsp;pole.