I overleaped the netlist here.........following is the controlled description.<br /><br />------------------------------------<br /><br />V_VSA vsa 0 DC=0<br />V_VDA vda 0 DC=3<br /><br />V_vip vip 0 DC=1<br />I_IIN 0 iin DC=2.5uA<br />v_vim vim 0 1 AC=1 $ ac source<br />R_AC_COUPLE vim vimz 1e9 ac=0 .<br /><br />R_self-bias vout vimz 1m ac=1e30 <br /><br />c_load vout vsa cval $ varying load capacitance<br />.TEMP 25<br />.options nomod numdgt=6 acout=0 runlvl=0 accurate post probe<br />.prot<br />.lib 'mm06.l' tt <br />.unprot<br /><br />.op<br />.param cval=0<br />.AC DEC 10 1m 10MEG<br />.print AC vdb(vout) vp(vout) v(*)<br /><br />.alter<br />.param cval=1p<br /><br />.alter <br />.param cval=10p<br /><br />.alter<br />.param cval=100p<br /><br />.end<br /><br />----------------------------------------------<br /><br /><br /><br />I'm fresh ,pls see my questions below: <br /><br />1,Through viewing the phase waveform,it has two turnings,whether means it has 2-pole response?and how did you calculate it?<br /><br />2,How does change in load capacitance affect pole location(s)?<br /><br /><br /><br />Need your helps, thanks in advance!<br /><br /><br /><br /> 相关链接:<a href='http://bbs.21ic.com/upfiles/img/20078/20078131293610.rar'>http://bbs.21ic.com/upfiles/img/20078/20078131293610.rar</a> |
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