逆变器电感电流补偿问题，ＴＩ的文档和我算的差太大了

<img src="http://bbs.21ic.com/upfiles/img/20083/200832413050325.gif"><br />上图为电感电流内环补偿前的ｂｏｄｅ图<br />电感电流内环使用ＰＩ补偿，我算出了电感电流内环补偿前的ｂｏｄｅ图，它的转折频率为１３００0ｒａｄ／ｓｅｃ，那么我该怎么选择补偿后的穿越频率呢?<br />下图为参数和ＴＩ补偿的结果<br /><img src="http://bbs.21ic.com/upfiles/img/20083/2008324125652839.gif">

%matlab函数计算Kip<br />clear<br />PI&nbsp;=&nbsp;3.1415926;<br /><br />Kpwm&nbsp;=&nbsp;400;<br />R&nbsp;=&nbsp;14.4;<br />C&nbsp;=&nbsp;20&nbsp;*&nbsp;10^(-6);<br />L&nbsp;=&nbsp;300&nbsp;*&nbsp;10^(-6);<br />Alpha&nbsp;=&nbsp;2.27&nbsp;/&nbsp;14.2;&nbsp;%&nbsp;2.27V/14.2A<br />Kii&nbsp;=&nbsp;13000;<br />Ficut&nbsp;=&nbsp;1200;%电流环穿越频率<br />s&nbsp;=&nbsp;2*PI*Ficut*i;<br />GIpiNum&nbsp;=&nbsp;Kpwm&nbsp;*&nbsp;Alpha&nbsp;*&nbsp;(s&nbsp;+&nbsp;Kii)&nbsp;*&nbsp;(R*C*s&nbsp;+&nbsp;1);<br />GIpiDen&nbsp;=&nbsp;R*L*C*s^3&nbsp;+&nbsp;L*s^2&nbsp;+&nbsp;R*s;<br />Kip&nbsp;=&nbsp;1/abs(GIpiNum/GIpiDen)