用AtmelStudio6.2跑mega16例程（34）INT0INT1记数

本程序，同时允许INT0,INT1中断。GICR = 0XC0也可写作 GICR = _BV(INT0) | _BV(INT1);

MCUCR = 0x0A是将两个中断设为下降沿触发.

以下是仿真的电路图：



以下是Studion6.2编译截图：

以下是程序：

复制

/*

 * GccApplication20.c

 *

 * Created: 2014-10-16 21:18:46

 *  Author: Administrator

 */ 



#define F_CPU 0x8000000UL

#include <avr/io.h>

#include <avr/interrupt.h>

#include <util/delay.h>

#include <stdint.h>



#define K1_CLEAR_ON() ((PIND & 0x10)== 0x00)

#define K2_CLEAR_ON() ((PIND & 0x20)== 0x00)



const uint8_t SEG_CODE[] = { 0xc0,0xf9,0xa4,0x80,0x99,0x92,0x82,0xf8,0x80,0x90,0xff};

const uint8_t SCAN_BITs[] = {0x20,0x10,0x08,0x04,0x02,0x01};

uint8_t Buffer_Counts[] = {0,0,0,0,0,0};

uint16_t Count_A = 0,Count_B = 0;



void Show_Counts()

{

     uint8_t i;

         

         Buffer_Counts[2] = Count_A/100;

         Buffer_Counts[1] = Count_A %100/10;

         Buffer_Counts[0] = Count_A %10;

         

         if(Buffer_Counts[2]== 0)

         {

                Buffer_Counts[2] = 10;

                if(Buffer_Counts[1] == 0) Buffer_Counts[1] = 10;

          }

         

         Buffer_Counts[5] = Count_B/100;

         Buffer_Counts[4] = Count_B % 100 /10;

         Buffer_Counts[3] = Count_B % 10;

         

         if(Buffer_Counts[5] == 0)

     {

                 Buffer_Counts[5] = 10;

                 if(Buffer_Counts[4] == 0)Buffer_Counts[4] = 10;

         }         

     

         for(i=0;i<6;i++)

         {

                 PORTC = SCAN_BITs[i];

                 PORTB = SEG_CODE[Buffer_Counts[i]];

                 _delay_ms(1);

         }

}

int main(void)

{

    DDRB = 0xFF;PORTB = 0xFF;

        DDRC = 0xFF;PORTC = 0xFF;

        DDRD = 0x00;PORTD = 0xFF;

        MCUCR = 0x0A;

        GICR = 0xC0;

        sei();

        

        while(1)

    {

        if(K1_CLEAR_ON())Count_A = 0;

                if(K2_CLEAR_ON())Count_B = 0;

                Show_Counts();    

        }

}





ISR(INT0_vect)

{

        Count_A++;

}



ISR(INT1_vect)

{

        Count_B++;

}