为什么进入LPM3，电流还有20MA

只看该作者 · 2016-5-14 07:44

通过RTC中断1S唤醒
void main(void)
{
WM_Initialize();             // System initialize

// Display "123456"
  LCD_Display0_8();

  while(1)
{
__bis_SR_register(LPM3_bits + GIE); // 进入 LPM3 w/ interrupt
}
}

void WM_Initialize(void)
{
WDTCTL = WDTPW + WDTHOLD;    // Stop watchdog
// WDTCTL = WDTPW + WDTCNTCL + WDTSSEL0 + WDTIS0 + WDTIS1;  // Set watchdog 16s

PM5CTL0 &= ~LOCKLPM5;       // Disable the GPIO power-on default high-impedance mode
// to activate previously configured port settings
GPIO_Config();             // GPIO initialize
CLOCK_Config();          // System clock initialize
LCD_Config();             // LCD module initialize
RTC_Config();
//P1SEL0 |= BIT5;  //配置P15为输入脚  20160506
   //    P1REN |= BIT5;
//P1REN &= ~BIT5; // to be comment  20160506
//TA0CTL = 0;  20160506
}
void CLOCK_Config()
{
P4SEL0 |= BIT1 + BIT2;                // Select pin4.1 pin4.2 as crystal function
do
{
CSCTL7 &= ~(XT1OFFG + DCOFFG); // Clear XT1 and DCO fault flag  清除 XT1 DCO 失效标志
SFRIFG1 &= ~OFIFG;
}while (SFRIFG1 & OFIFG);          // Test oscillator fault flag  如果失效标志存在

CSCTL4 = SELA__XT1CLK; // IMPORTANT. Select ACLK = XT1 = 32768Hz
}
void LCD_Config()
{
uint8_t ui8Cnt;
uint8_t *pLCD = (uint8_t *)&LCDM0;
for (ui8Cnt = 13; ui8Cnt > 0; ui8Cnt--) // Clear LCD memory
*pLCD++ = 0x00; // CLR LCD

SYSCFG2 |= LCDPCTL;       // R13/R23/R33/LCDC1/LCDC2 pins selected  设置 LCD功耗

LCDPCTL0 = 0xFFFF;
LCDPCTL1 = 0x01FF; //设置 LCD管脚 L0~L24 pins selected

LCDVCTL = LCDSELVDD + LCDCPEN; // Mode 2 设置降低LCD 功耗片上电荷泵

LCDCSSEL0 = 0x000F; // 设置公共极  COM0~3
LCDCSSEL1 = 0x0000;

  LCDM0 = 0x21;                                           // L0 = COM0, L1 = COM1
  LCDM1 = 0x84;

LCDCTL0 |= LCD4MUX + LCDLP + LCDON; // 打开LCD: 4-mux 模式
}
void RTC_Config()
{
RTCCTL = RTCSS__XT1CLK + RTCSR + RTCPS__1 | RTCIE;
RTCMOD = 32768-1;                //1s
tRTCData.ui8Year = 14;             // RTC initialize
tRTCData.ui8Month = 7;
tRTCData.ui8Day = 30;
tRTCData.ui8Hour = 23;
tRTCData.ui8Minute = 59;
tRTCData.ui8Second = 55;
}

只看该作者 · 2016-5-14 07:46

// RTC interrupt service routine
#pragma vector=RTC_VECTOR
__interrupt void RTC_ISR(void)
{
switch(__even_in_range(RTCIV,RTCIV_RTCIF))
{
case RTCIV_NONE: break;          // No interrupt

case RTCIV_RTCIF:                // RTC Overflow
{
uint8_t ui8Days = 31;
uint8_t *pAddress;             // For monthly data storage

tRTCData.ui8Second++;
。。。
__low_power_mode_off_on_exit();  //退出中断时唤醒CPU
}
break;
default: break;
}
}