请问STM32串口通讯时任何设置9位数据位，就是1位地址码+8位

只看该作者 · 2009-1-1 10:18

  USART_InitStructure.USART_BaudRate = 9600;
  USART_InitStructure.USART_WordLength = USART_WordLength_9b;
  USART_InitStructure.USART_StopBits = USART_StopBits_1;
  USART_InitStructure.USART_Parity = USART_Parity_No;
  USART_InitStructure.USART_HardwareFlowControl =  USART_HardwareFlowControl_None;
  USART_InitStructure.USART_Mode = USART_Mode_Rx | USART_Mode_Tx;
  USART_InitStructure.USART_Clock = USART_Clock_Disable;
  USART_InitStructure.USART_CPOL = USART_CPOL_Low;
  USART_InitStructure.USART_CPHA = USART_CPHA_2Edge;
  USART_InitStructure.USART_LastBit = USART_LastBit_Disable;

  /* Configure USART1 */
  USART_Init(USART1, &USART_InitStructure);

  /* Enable the USART1 */
  USART_Cmd(USART1, ENABLE);

  /* Set the USART1 Address */
  USART_SetAddress(USART1, 0x1);
请问上面一句是否就是设置USART1的第9位，就是地址码

如果我要把地址位置0，是否就是USART_SetAddress(USART1, 0x0);