参考TI例程如下：
interrupt void cpu_timer0_isr(void)
{
CpuTimer0.InterruptCount++;
// Acknowledge this interrupt to receive more interrupts from group 1
PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;
}
我将程序做修改如下：
interrupt void cpu_timer0_isr(void)
{
Dout8 = 1;
Dout7 = 1;
ad_conv();
Dout7 = 0;
DA_Out();
Dout8 = 0;
PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;// Acknowledge this interrupt to receive more interrupts
//from group 1 PIEACK_GROUP1=1
}
用示波器测得 Dout7输出正常， Dout8输出为50us的窄脉冲；C:\Users\Administrator\Desktop |
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