本帖最后由 200920705147 于 2010-6-22 21:26 编辑
*************************************************************************/
// ---------------
// LED显示摇棒
// ---------------
// 作者：nim 于 http://www.21icbbs.com 2005-1-7
//
// email: linyige@yahoo.com
//
// 本设计版权归作者所有，请勿擅自用于商业目的，转载请注明作者及出处
/*************************************************************************/
#include <reg51.h>
#define SEG 17 //每帧图片分成17列来显示
#define INTERVAL 20 //每幅图片在左右摇摆20次后换下一幅
typedef unsigned char uchar;
typedef unsigned int uint;
code char pattern[17][3]={ //3幅图片的字模
{0xff,0xff,0xff},
{0xff,0xff,0xff},
{0xff,0xff,0xff},
{0xff,0x9f,0xff},
{0xff,0x6f,0xf9},
{0xff,0x77,0x65},
{0xfe,0xbb,0x1e},
{0x7e,0xdd,0xfe},
{0x00,0xee,0xfe},
{0x7e,0xdd,0xfe},
{0xfe,0xbb,0x1e},
{0xff,0x77,0x65},
{0xff,0x6f,0xf9},
{0xff,0x9f,0xff},
{0xff,0xff,0xff},
{0xff,0xff,0xff},
{0xff,0xff,0xff},
};
uchar phase,th1,tl1,index,count;
main()
{
EA=0;
EX0=1;
ET1=1;
PX0=1;
IT0=1;
TMOD=0x11;
index=0;
EA=1;
while(1)
{
}
}
void Int0_Handle(void) interrupt 0 using 2
{
uint t0_time;
TR0=0;
TR1=0;
TF1=0;
t0_time=TH0<<8|TL0;
TL0=0;
TH0=0;
TR0=1;
t0_time=65535-t0_time/SEG;
th1=t0_time/256;
TH1=th1;
tl1=t0_time % 256;
TL1=tl1;
if (count<3*INTERVAL){ //3幅图片循环
count++;
}
else{
count=0;
}
index=count/INTERVAL;
if (th1!=0xff || tl1!=0xff){ //如果摆动特别慢，定时器溢出就不显示
phase=0;
TR1=1;
}
else{
TR1=0;
}
}
void Timer1(void) interrupt 3 using 3
{
if (phase<SEG) //17段依次显示
{
P1=pattern[phase][index];
phase++;
TH1=th1;
TL1=tl1;
}字模为什么17列
}该程序中字模怎样设置的，
|
楼主
标题置顶
标题高亮
