module counter5 (clk,clr,q,cout);
input clk,clr;
output [5:1] q;
output cout;
reg [5:1] q;
always @ (posedge clk or negedge clr)
begin
if (clk) q=0;
else
q=(q=6'h32)?0:(q+1);
end
endmodule
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求程序的解释,想知道程序完成计数的逻辑过程,,, |