#include "math.h"
void kfft(pr,pi,n,k,fr,fi)
int n,k;
double pr[],pi[],fr[],fi[];
{
int it,m,is,i,j,nv,l0;
double p,q,s,vr,vi,poddr,poddi;
for (it=0; it<=n-1; it++) //将pr[0]和pi[0]循环赋值给fr[]和fi[]
{
m=it;
is=0;
for(i=0; i<=k-1; i++)
{
j=m/2;
is=2*is+(m-2*j);
m=j;
}
fr[it]=pr[is];
fi[it]=pi[is];
}
pr[0]=1.0;
pi[0]=0.0;
p=6.283185306/(1.0*n);
pr[1]=cos(p); //将w=e^-j2pi/n用欧拉公式表示
pi[1]=-sin(p);
for (i=2; i<=n-1; i++) //计算pr[]
{
p=pr[i-1]*pr[1];
q=pi[i-1]*pi[1];
s=(pr[i-1]+pi[i-1])*(pr[1]+pi[1]);
pr[i]=p-q; pi[i]=s-p-q;
}
for (it=0; it<=n-2; it=it+2)
{
vr=fr[it];
vi=fi[it];
fr[it]=vr+fr[it+1];
fi[it]=vi+fi[it+1];
fr[it+1]=vr-fr[it+1];
fi[it+1]=vi-fi[it+1];
}
m=n/2;
nv=2;
for (l0=k-2; l0>=0; l0--) //蝴蝶操作
{
m=m/2;
nv=2*nv;
for (it=0; it<=(m-1)*nv; it=it+nv)
for (j=0; j<=(nv/2)-1; j++)
{
p=pr[m*j]*fr[it+j+nv/2];
q=pi[m*j]*fi[it+j+nv/2];
s=pr[m*j]+pi[m*j];
s=s*(fr[it+j+nv/2]+fi[it+j+nv/2]);
poddr=p-q;
poddi=s-p-q;
fr[it+j+nv/2]=fr[it+j]-poddr;
fi[it+j+nv/2]=fi[it+j]-poddi;
fr[it+j]=fr[it+j]+poddr;
fi[it+j]=fi[it+j]+poddi;
}
}
for (i=0; i<=n-1; i++)
{
pr[i]=sqrt(fr[i]*fr[i]+fi[i]*fi[i]); //幅值计算
}
return;
}
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