其中a=bcd(sum)返回数组的值，为什么不行！

只看该作者 · 2007-3-18 17:41

#include<reg51.h>

#define uchar unsigned char
void delay()
{
uchar i,j,k;
   for(i=0;i<10;i++)
     for(j=0;j<100;j++)
       for(k=0;k<6;k++)
          { ;}
}
uchar conv(uchar digit)
{uchar mid;
  switch(digit)
  {case  0:mid=0x3f;
         break;
   case  1:mid=0x06;
         break;
   case  2:mid=0x5b;
         break;
   case  3:mid=0x4f;
         break;
   case  4:mid=0x66;
         break;
   case  5:mid=0x6d;
         break;
   case  6:mid=0x7d;
         break;
   case  7:mid=0x07;
         break;
   case  8:mid=0x7f;
         break;

   case  9:mid=0x6f;
         break;
   default:break;
  }
   return mid;
}
uchar *bcd(uchar k)
{uchar car[4];
car[0]=k%10;
k=k/10;
if(car[0]>9)
{ car[0]=car[0]-10;
  k=k+1;}
car[1]=k%10;
k=k/10;
if(car[1]>9)
{ car[1]=car[1]-10;
  k=k+1;}
  car[2]=k%10;
k=k/10;
if(car[2]>9)
{ car[2]=car[2]-10;
  k=k+1;}
car[3]=k%10;
k=k/10;
if(car[3]>9)
{ car[3]=car[3]-10;
  k=k+1;}
  return car;}
void main(void)
{ uchar xdata temp[10];
  uchar i,j;
  uchar a[4];
  int sum=0;

for(i=0;i<3;i++)
   temp=i+1;
  for(j=0;j<3;j++)
    sum=temp[j]+sum;

     for( ; ;)
    {a=bcd(sum);
     P3=0x01;
    for(i=0;i<4;i++)
    {P1=conv(a);
     delay2();
     P3=P3<<1;}
}
其中a=bcd(sum)返回数组首地址的值，为什么不行！