文字池答案是否正确
UARTLCON0 EQU 0x3FFD000
UARTCONT0 EQU 0x3FFD004
UARTSTAT0 EQU 0x3FFD008
UTXBUF0 EQU 0x3FFD00C
UARTBRD0 EQU 0x3FFD014
AREA Init,CODE,READONLY
ENTRY
;**************************************************
;LED Display
;**************************************************
LDR R1,=0x3FF5000
LDR R0,=&ff
STR R0,[R1]
LDR R1,=0x3FF5008
LDR R0,=&ff
STR R0,[R1]
;*************************************************
;UART0 line control register
;*************************************************
LDR R1,=UARTLCON0
LDR R0,=0x03
STR R0,[R1]
;**************************************************
;UART0 control regiser
;**************************************************
LDR R1,=UARTCONT0
LDR R0,=0x9
STR R0,[R1]
;**************************************************
;UART0 baud rate divisor regiser
;Baudrate=19200，对应于50MHz 的系统工作频率
;***************************************************
LDR R1,=UARTBRD0
LDR R0,=0x500
STR R0,[R1]
;***************************************************
;Print the messages!
;***************************************************
LOOP
LDR R0,=Line1
BL PrintLine
LDR R0,=Line2
BL PrintLine
LDR R0,=Line3
BL PrintLine
LDR R0,=Line4
BL PrintLine
LDR R1,=0x7FFFFF
LOOP1
SUBS R1,R1,#1
BNE LOOP1
B LOOP
;***************************************************
;Print line
;***************************************************
PrintLine
MOV R4,LR
MOV R5,R0
Line
LDRB R1,[R5],#1
AND R0,R1,#&FF
TST R0,#&FF
MOVEQ PC,R4
BL PutByte
B Line
PutByte
LDR R3,=UARTSTAT0
LDR R2,[R3]
TST R2,#&40
BEQ PutByte
LDR R3,=UTXBUF0
STR R0,[R3]
MOV PC,LR
Line1 DCB
&A,&D,"******************************************************************",0
Line2 DCB &A,&D,"Chinese Academy of Sciences,Institute of Automation,Complex System
Lab.",0
Line3 DCB &A,&D," ARM Development Board Based on Samsung ARM S3C4510B.",0
Line4 DCB
&A,&D,&A,&D,&A,&D,&A,&D,&A,&D,&A,&D,&A,&D,&A,&D,&A,&D,&A,&D,&A,&D,&A,&D,&A,&D,&
A,&D,&A,&D,0
END |
楼主
