AD采集的问题

只看该作者 · 2017-7-8 22:04

#include <hidef.h>    /* common defines and macros */
#include "derivative.h"    /* derivative-specific definitions */

#define BUS_CLOCK  32000000
#define OSC_CLOCK  16000000
#define FAN1 PORTB_PB2
#define FAN1_dir DDRB_DDRB2
#define FAN2 PORTA_PA3
#define FAN2_dir DDRA_DDRA3
#define FAN3 PORTA_PA4
#define FAN3_dir DDRA_DDRA4
#define FAN4 PORTA_PA5
#define FAN4_dir DDRA_DDRA5
#define FAN5 PORTD_PD7
#define FAN5_dir DDRD_DDRD7
#define FAN6 PORTD_PD6
#define FAN6_dir DDRD_DDRD6
#define FAN7 PORTD_PD5
#define FAN7_dir DDRD_DDRD5
#define FAN8 PORTD_PD4
#define FAN8_dir DDRD_DDRD4
#define FAN9 PORTA_PA7
#define FAN9_dir DDRA_DDRA7
#define FAN10 PORTA_PA6
#define FAN10_dir DDRA_DDRA6

const unsigned int oumu[]={
  10450,10000,9574,9166,8778,8480,8058,7724,7404,7098,6808,6532,6268,6015,5776,5546,5326,5118,4918,4726,4544,4368,4202
};
const unsigned int temp[]={
  24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47
};
unsigned char chanel;
unsigned int AD_in0,AD_in1,AD_in2,AD_in3,AD_in4,AD_in8,AD_in9,AD_in10,AD_in11,AD_in12;
unsigned int y=0;
unsigned char h;
float a,b;

void INIT_PLL(){    //初始化锁相环
  CLKSEL &=0x7f;
  PLLCTL &=0x8F;
  CRGINT &=0xDF;

  #if (BUS_CLOCK == 40000000)
   SYNR=0x44;
  #elif (BUS_CLOCK ==32000000)
   SYNR=0x43;
  #elif (BUS_CLOCK == 24000000)
   SYNR=0x42;
  #endif

  REFDV=0x81;
  PLLCTL |=0x70;
  asm NOP;
  asm NOP;
  while(!(CRG**&0x08));
  CLKSEL=0x80;
}

void INIT_AD(){       //初始化AD转换
  ATD0CTL2=0x40;  //启动A/D模块，快速清零，禁止中断
  ATD0CTL1_SRES=2;//选用12位模数转换
  ATD0CTL3=0x88;  //每次只转换一个通道
  ATD0CTL4=0x07;  //AD模块时钟频率为2MHz
}

unsigned int AD_capture(chanel)    //启动AD转换
{
unsigned int AD_data;
switch(chanel)
{
  case 0:
ATD0CTL5 = 0x00; //转换AD00
while(!ATD0STAT0_SCF);
AD_data = ATD0DR0;
break;

  case 1:
ATD0CTL5 = 0x01; //转换AD01
while(!ATD0STAT0_SCF);
AD_data = ATD0DR0;
break;

  case 2:
ATD0CTL5 = 0x02; //转换AD02
while(!ATD0STAT0_SCF);
AD_data = ATD0DR0;
break;

  case 3:
ATD0CTL5 = 0x03; //转换AD03
while(!ATD0STAT0_SCF);
AD_data = ATD0DR0;
break;

  case 4:
ATD0CTL5 = 0x04; //转换AD04
while(!ATD0STAT0_SCF);
AD_data = ATD0DR0;
break;

  case 8:
ATD0CTL5 = 0x08; //转换AD08
while(!ATD0STAT0_SCF);
AD_data = ATD0DR0;
break;

  case 9:
ATD0CTL5 = 0x09; //转换AD09
while(!ATD0STAT0_SCF);
AD_data = ATD0DR0;
break;

  case 10:
ATD0CTL5 = 0x0a; //转换AD10
while(!ATD0STAT0_SCF);
AD_data = ATD0DR0;
break;

  case 11:
ATD0CTL5 = 0x0b; //转换AD11
while(!ATD0STAT0_SCF);
AD_data = ATD0DR0;
break;

  case 12:
ATD0CTL5 = 0x0c; //转换AD12
while(!ATD0STAT0_SCF);
AD_data = ATD0DR0;
break;

}
return(AD_data);
}

void hanshu() {                                  //电阻值算法
  a=10*AD_capture(chanel)/(4.4-AD_capture(chanel));
  b=a*1000;
  y=(int)b;

}

void main(void) {

  /* put your own code here */
DisableInterrupts;
INIT_PLL();
INIT_AD();
FAN1_dir=1;
FAN2_dir=1;
FAN3_dir=1;
FAN4_dir=1;
FAN5_dir=1;
FAN6_dir=1;
FAN7_dir=1;
FAN8_dir=1;
FAN9_dir=1;
FAN10_dir=1;
FAN1=1;
h=0;
EnableInterrupts;


for(;;){

   hanshu();
while(!(y<=oumu[h]&&y>=oumu[h+1])) //将阻止与已知阻止表比较
  {
h++;
if (h==24){
   h=0;
}
  }
  AD_in(chanel)=temp[h];



  if (AD_in0>45)
   FAN1=0;
  else if (AD_in0<25)
   FAN1=1;
  if (AD_in1>45)
   FAN2=0;
  else if (AD_in1<25)
   FAN2=1;
  if (AD_in2>45)
   FAN3=0;
  else if (AD_in2<25)
   FAN3=1;
  if (AD_in3>45)
   FAN4=0;
  else if (AD_in3<25)
   FAN4=1;
  if (AD_in4>45)
   FAN5=0;
  else if (AD_in4<25)
   FAN5=1;
  if (AD_in8>45)
   FAN6=0;
  else if (AD_in8<25)
   FAN6=1;
  if (AD_in9>45)
   FAN7=0;
  else if (AD_in9<25)
   FAN7=1;
  if (AD_in10>45)
   FAN8=0;
  else if (AD_in10<25)
   FAN8=1;
  if (AD_in11>45)
   FAN9=0;
  else if (AD_in11<25)
   FAN9=1;
  if (AD_in12>45)
   FAN10=0;
  else if (AD_in12<25)
   FAN10=1;
}

}




/* loop forever */
  /* please make sure that you never leave main */

  这是程序，我现在纠结的问题是，算法完成之后我只会设置一路AD的转换值，我想让她用switch case语句那样，自己可以查找chanel，不知道能不能实现，肯定各位大哥大姐们，棒棒忙！！

只看该作者 · 2017-7-9 11:09

AD采集的问题

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