[url=home.php?mod=space&uid=72445]@[/url] stm32f030f4p6 asm
[url=home.php?mod=space&uid=72445]@[/url] os
.thumb
.syntax unified
.section .data
.equ duizhanding, 0x20001000 @ 堆栈顶
.equ dqrwyxj, 0x20000044 @ 当前任务优先级
.equ xtzgyxj, 0x20000048 @ 系统里最高优先级
.equ dangqian, 0x2000004c @ 当前任务指向控制块里指针
.equ dengyunxing, 0x20000050 @ 待运行任务指向控制块里指针
.equ jiuxubiao, 0x20000054 @ 就绪查找表8个任务
@ 保留0X20
.equ renwubiao, 0x20000074 @ 指向任务控制块地址的指针表
@保留0x20
.equ renwukongzhikuai, 0x20000094 @ 任务控制块地址
@每个控制块4个数据，+0堆栈顶，+4任务时间,+8优先级，+C
.equ renwuduizhan, 0x20000500 @ 任务堆栈顶
.section .text
vectors: @向量表
.word duizhanding
.word _start + 1 @复位向量
.word _nmi_handler + 1
.word _hard_fault + 1
.word 0
.word 0
.word 0
.word 0
.word 0
.word 0
.word 0
.word _svc + 1
.word 0
.word 0
.word _pendsvzhongduan + 1
.word _systickzhongduan + 1
_start:
_shizhong: @时钟设置
ldr r2, = 0x40022000 @FLASH访问控制
movs r1, # 0x32
str r1, [r2]
ldr r0, = 0x40021000 @ rcc
@0x34时钟控制寄存器 2 (RCC_CR2)
movs r1, # 0x01
str r1, [r0, # 0x34] @ HSI开14M时钟
_dengdai14mshizhongwending: @等14M时钟稳定
ldr r1, [r0, # 0x34]
lsls r1, r1, # 30 @ 左移30位
bpl _dengdai14mshizhongwending @ 等待14M时钟稳定
_neicunqingling: @ 0x1000的内存清零
@ 1K=1024BIT=0X400
ldr r0, = 0x20000000
movs r1, # 0
ldr r3, = 0x1000
_neicunqinglingxunhuan: @ 内存清零循环
subs r3, # 4
str r1, [r0, r3]
bne _neicunqinglingxunhuan @
_systick: @ systick定时器初始化
@ 0xe000ed20 30-31 youxianji
@ 22-23 PENDSV
ldr r0, = 0xe000ed20
ldr r1, = 0x00c00000
str r1, [r0] @设置优先级
ldr r0, = 0xe000e010
ldr r1, = 100
str r1, [r0, # 4]
str r1, [r0, # 8]
movs r1, # 0x07
str r1, [r0]
_renwuchushihua1: @ 空闲任务初始化
ldr r0, = renwuduizhan @ 任务堆栈顶
ldr r1, = _kongxianrenwu @ 空闲任务地址
adds r1, r1, # 1 @ +1进入thumb
ldr r2, = 0x01000000 @ xpsr
movs r3, # 0
mov r7, r2 @ pc
mov r6, r1
mov r5, r3
mov r4, r3
mov r12, sp @ 当前堆栈指针放到R12
mov sp, r0 @ 当前堆栈指针等于任务堆栈顶
push {r0-r7} @ 把刚才数据保存到任务堆栈
push {r4-r7}
ldr r0, = renwukongzhikuai @ 任务控制块地址
ldr r1, = renwuduizhan @ 任务堆栈顶
str r1, [r0] @ 空闲任务的堆栈顶写到任务控制块
ldr r1, = renwubiao @ 任务表
str r0, [r1] @ 把任务控制块地址写到任务表
_renwu1chushihua: @ 同上面一样，只是地址偏移
ldr r0, = renwuduizhan
ldr r1, = 0x100
subs r0, r0, r1
ldr r1, = _renwu1
adds r1, r1, # 1
ldr r2, = 0x01000000
movs r3, # 0
mov r7, r2
mov r6, r1
mov r5, r3
mov r4, r3
mov sp, r0
push {r0-r7}
push {r0-r3}
ldr r0, = renwukongzhikuai
ldr r1, = renwuduizhan
ldr r2, = 0x100
subs r1, r2
adds r0, # 0x10
str r1, [r0]
ldr r1, = renwubiao
str r0, [r1, # 0x04]
ldr r0, = jiuxubiao @ 就绪表
movs r1, # 1
str r1, [r0] @ 空闲任务一直就绪
str r1, [r0, # 0x04] @ 任务1就绪
mov sp, r12 @ 恢复堆栈指针
movs r0, # 0
msr psp, r0 @ PSP清零
bl _diaodu @ 自动调度
_dddd:
b _dddd
_kongxianrenwu: @ 空闲任务
ldr r0, = 0x100 @ 任务1延时时间
bl _renwushijian @ 判断任务1到没到，到了执行调度
ldr r0, = 0x20000704 @ 空闲任务执行次数
ldr r1, [r0]
adds r1, r1, # 4
str r1, [r0]
b _kongxianrenwu
_renwu1:
ldr r0, = jiuxubiao @ 就绪表
movs r1, # 0
str r1, [r0, # 0x04] @ 任务1放开CPU
ldr r0, = 0x20000700 @ 任务1执行次数
ldr r1, [r0]
adds r1, r1, # 1
str r1, [r0]
bl _diaodu @ 调度
b _renwu1
_renwushijian: @ 任务多长时间执行一次
ldr r2, = renwukongzhikuai @ 任务控制块
ldr r1, [r2, # 0x14] @ 读出任务1时间
cmp r1, r0 @ 等不等于R0
bls _renwushijianfanhui @ 小于返回
ldr r0, = jiuxubiao @ 大于执行我
movs r1, # 1
str r1, [r0, # 0x04] @ 就绪表里面任务1写1表示就绪
movs r1, # 0
str r1, [r2, # 0x14] @ 清零任务1时间
b _diaodu @ 调度
_renwushijianfanhui:
bx lr
_diaodu:
ldr r0, = jiuxubiao @就绪表
movs r1, # 0x08 @ 8个任务， 每个任务用32位表示
lsls r1, # 2 @ R1等于32
_zhaozuigao: @ 从高开始减，找最高优先级任务
subs r1, r1, # 4
ldr r2, [r0, r1]
cmp r2, # 1
bne _zhaozuigao @循环找，由于空闲任务一直就绪
@没有别的任务就执行空闲的
_zhaodaozuigao: @ 找到了最高优先级的了
ldr r0, = renwubiao @ 任务表
adds r0, r1 @ 任务表指针偏移
ldr r2, = dengyunxing @ 等运行
str r0, [r2] @ 任务表偏移指针写道等运行
ldr r0, = 0xe000ed04 @ 触发pendsv中断
ldr r1, = 0x10000000
str r1, [r0]
bx lr
_nmi_handler:
bx lr
_hard_fault:
bx lr
_svc:
bx lr
_pendsvzhongduan: @PENDSV中断
cpsid i @ 关中断
mrs r0, psp @ 读PSP当前地址到R0
cmp r0, # 0 @ r0和0比较
beq _qiehuanrenwu @ 等于0执行任务切换
mov r12, sp @ 堆栈指针保存到R12
mov sp, r0 @ SP等于r0
push {r4-r7} @ 把R4-R7保存到堆栈最低四个32位
_qiehuanrenwu: @ 切换任务
ldr r0, = dangqian @ 当前任务指针
ldr r1, = dengyunxing @ 等待运行指针
ldr r2, [r1] @ 取出任务表里的指针
str r2, [r0] @ 任务表里的指针写到待运行指针
ldr r0, [r2] @ R0等于任务控制块地址表
ldr r0, [r0] @ 取出任务堆栈顶
subs r0, # 0x30 @ R0等于堆栈底
mov sp, r0 @ SP等于R0
pop {r4-r7} @ 弹出R4-R7
mov r1, lr @ lr写到R1
movs r2, # 0x04 @ R2等于0X04 选择LR第2位
orrs r1, r2 @ R1或R2
mov lr, r1 @ 写回到LR
mov r0, sp @ R0等于堆栈底加0X10
msr psp, r0 @ 写到PSP
mov sp, r12 @ 恢复SP
cpsie i @ 开中断
bx lr @ 返回
_systickzhongduan:
ldr r0, = 0xe0000d04
ldr r1, = 0x02000000
str r1, [r0] @ 清除SYSTICK中断
ldr r0, = renwukongzhikuai @ 任务控制块
ldr r1, [r0, # 0x14] @ 任务1的任务时间
adds r1, r1, # 1 @ 加1
str r1, [r0, # 0x14] @ 写回去
bx lr @ 返回
楼主
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楼主告诉我们要想工资高，还得写汇编，上级要求交出来都没问题，别人也看不懂，所以汇编才是体现自己的价值啊。
