我倒塌了~~~51就是按大端存储的,为何打PP???
unsigned char databuf[24];//64位BCD加法缓冲区
unsigned char DataAdd(unsigned char *,unsigned char *,unsigned char);
void main()
{
unsigned char val;
//8位BCD加法(12 + 78 = 90)
(unsigned char)databuf[1] = 0x12;
(unsigned char)databuf[2] = 0x78;
val = DataAdd(&databuf[1], &databuf[2], 1);//结果在val和databuf[1]中
//16位BCD加法(1234 + 5678 = 6912)
(unsigned int)databuf[2] = 0x1234;
(unsigned int)databuf[4] = 0x5678;
val = DataAdd(&databuf[2], &databuf[4], 2);//结果在val和databuf[0]~databuf[1]中
//24位BCD加法(123456 + 456789 = 580245)
(unsigned char)databuf[3] = 0x12;
(unsigned int) databuf[4] = 0x3456;
(unsigned char)databuf[6] = 0x45;
(unsigned int) databuf[7] = 0x6789;
val = DataAdd(&databuf[3], &databuf[6], 3);//结果在val和databuf[0]~databuf[2]中
//32位BCD加法(12345678 + 88888888 = 1 01234566)
(unsigned long)databuf[4] = 0x12345678L;
(unsigned long)databuf[8] = 0x88888888L;
val = DataAdd(&databuf[4], &databuf[8], 4);//结果在val和databuf[0]~databuf[3]中
//64位BCD加法(1111111122222222 + 8888888899999999 = 1 0000000022222221)
(unsigned long)databuf[8] = 0x11111111L;
(unsigned long)databuf[12] = 0x22222222L;
(unsigned long)databuf[16] = 0x88888888L;
(unsigned long)databuf[20] = 0x99999999L;
val = DataAdd(&databuf[8], &databuf[16], 8);//结果在val和databuf[0]~databuf[7]中
while(1)
{
}
}
unsigned char DataAdd(unsigned char *DataOneDptr,unsigned char *DataTwoDptr,unsigned char DataLend)
{
unsigned char One, Two, Tmp;//中间变量
unsigned int Sum = 0;//考虑CY位故取整型
while(DataLend) {//不能DataLend--或--DataLend
DataLend --;//调整到正确的数组位置
One = DataOneDptr[DataLend];//取出正确的被加数
Two = DataTwoDptr[DataLend];//取出正确的加数
Sum = One + Two + Sum;//二进制求和(注意上次低位向高位的进位)
Tmp = (One & 0xf0) + (Two & 0xf0);//为半进位做准备
if ((Tmp != (Sum & 0xf0)) || ((Sum & 0x0f) > 9)) {//BCD码低4位调整
Sum += 6;//凡加减10或9的都是"混球"~~~
}
if (Sum >= 0xa0) {//BCD码高4位调整
Sum += 0x60;//注意"混球"~~~
}
databuf[DataLend] = Sum;//只存入低8位
Sum >>= 8;//保留高8位做为下次低位向高位的进位
}
return Sum;//返回溢出标志(最高1位)
}
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