有点长,请高手别介意:dizzy:
第七课的第三题:
以16进制发送一个0-65536之间的任一数,当单片机收到后在数码管上动态显示出来,波特率自定。
这是我写的,发送数据数码管显示不了前三位,为毛?- #include<reg52.h>
- unsigned int num,aa;
- unsigned char flag,num1,num2,num3,num4,num5,num6;
- sbit dula=P2^6;
- sbit wela=P2^7;
- unsigned char code table[]={0x3f,0x06,0x5b,0x4f,
- 0x66,0x6d,0x7d,0x07,
- 0x7f,0x6f,0x77,0x7c,
- 0x39,0x5e,0x79,0x71,
- 0x76,0x79,0x38,0x3f};
- void led_dispaly(unsigned int num);
- void delay(unsigned int z);
- void ser_init()
- {
- TMOD=0x20;
- TH1=0xfd;
- TL1=0xfd;
- TR1=1;
- SM0=0;
- SM1=1;
- REN=1;
- EA=1;
- ES=1;
- flag=0;
- num=0;
- aa=0;
- }
- void main()
- {
- ser_init();
- while(1)
- {
- if(flag==1)
- {
- ES=0;
- flag=0;
- SBUF=aa;
- while(!TI);
- TI=0;
- ES=1;
- while(RI==0)
- {
- led_dispaly(num);
- }
- }
- }
- }
- void ser() interrupt 4
- {
- RI=0;
- flag=1;
- num=SBUF;
- aa=SBUF;
- }
- void led_dispaly(unsigned int num0)
- {
- num1=num0/100000%10;
- num2=num0/10000%10;
- num3=num0/1000%10;
- num4=num0/100%10;
- num5=num0/10%10;
- num6=num0%10;
- P0=0xff;
- wela=1;
- P0=0xfe;
- wela=0;
- dula=1;
- P0=table[num1];
- dula=0;
- delay(1);
- P0=0xff;
- P0=0xfd;
- wela=0;
- dula=1;
- P0=table[num2];
- dula=0;
- delay(1);
- P0=0xff;
- wela=1;
- P0=0xfb;
- wela=0;
- dula=1;
- P0=table[num3];
- dula=0;
- delay(1);
- P0=0xff;
- wela=1;
- P0=0xf7;
- wela=0;
- dula=1;
- P0=table[num4];
- dula=0;
- delay(1);
- P0=0xff;
- wela=1;
- P0=0xef;
- wela=0;
- dula=1;
- P0=table[num5];
- dula=0;
- delay(1);
- P0=0xff;
- wela=1;
- P0=0xdf;
- wela=0;
- dula=1;
- P0=table[num6];
- dula=0;
- delay(1);
- }
- void delay(unsigned int z) //延时函数,delay(1);延时1ms 11.0592MHZ
- {
- unsigned int i,j;
- for(i=z;i>0;i--)
- for(j=110;j>0;j--);
- }
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