2808定时器的问题

发表于 2013-1-9 20:25

InitPll(DSP28_PLLCR,DSP28_CLKINDIV);  定时器配置的DSP28_PLLCR=5，DSP28_CLKINDIV=0（就是说使能2分频）外部晶振是20MHz，所以SYSCLK是50MHz。中断函数如下：
interrupt void cpu_timer0_isr(void){
      CpuTimer0.InterruptCount++;
      EALLOW;
      GpioCtrlRegs.GPAPUD.bit.GPIO8 = 0;
   GpioCtrlRegs.GPAMUX1.bit.GPIO8 = 0;
      GpioCtrlRegs.GPADIR.bit.GPIO8 = 1;
   GpioDataRegs.GPATOGGLE.bit.GPIO8 = 1;
EDIS;
  StopCpuTimer0();
   DISABLE_TIMER1_INT;
ConfigCpuTimer(&CpuTimer0, 50, 1000000);
StartCpuTimer0();
   PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;
}就是说电平是每隔1s翻转一次吧，就是说灯亮1s，灭1s。但是实际板子上面，灯是亮0.5s，灭0.5s，为什么会这样啊，找了半天都没找出答案来。

发表于 2013-1-9 20:26

nterrupt void cpu_timer0_isr(void)
{          CpuTimer0.InterruptCount++;  // BUZZ_CLK_GENER;
      EALLOW;
      GpioCtrlRegs.GPAPUD.bit.GPIO8 = 0;                                                                         // Enable pullup on GPIO8
GpioCtrlRegs.GPAMUX1.bit.GPIO8 = 0;                                                                         // GPIO8 = GPIO
GpioCtrlRegs.GPADIR.bit.GPIO8 = 1;                                                                         // GPIO8 = output
GpioDataRegs.GPATOGGLE.bit.GPIO8 = 1; EDIS; // Acknowledge this interrupt to receive more interrupts from group 1
StopCpuTimer0();                                                                                              //停止计数
DISABLE_TIMER1_INT;                                                                                              //不使能定时中断
      ConfigCpuTimer(&CpuTimer0, 50, 1000000);                      //设置定时时间
      StartCpuTimer0();                                                                                              //重启定时器
         PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;                      //ACK标志位写1清零
}

2808定时器的问题

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