本帖最后由 ddllxxrr 于 2016-1-27 20:35 编辑
位取反，自已起来还得至少三到四行代码，最起码得判断语句加上。
而CodeVisionAVR就很简单，只要在头文件包含<iobits.h>就可以了
它的函数有以下几个：
SETBIT（port,n）;设置端口第n位为1
CLRBIT (port,n);设置端口第n位为0
TGLBIT（port,n）；设置端口第n位为来回反转
EQUBIT（port,n）;给端口第n位为赋值
为了检验我特地编了个工程
建立时只设了端口B的方向：
以下是形成的程序：我只是在while里添了个反转函数
/*******************************************************
This program was created by the CodeWizardAVR V3.24
Automatic Program Generator
?Copyright 1998-2015 Pavel Haiduc, HP InfoTech s.r.l.
http://www.hpinfotech.com
Project :
Version :
Date : 2016/1/27
Author :
Company :
Comments:
Chip type : ATxmega128B1
Program type : Application
AVR Core Clock frequency: 2.000000 MHz
Memory model : Small
Data Stack size : 2048
*******************************************************/
// I/O Registers definitions
#include <io.h>
// Standard Input/Output functions
#include <stdio.h>
#include <iobits.h>
// Clock System initialization function
#include "clock_init.h"
// Event System initialization function
#include "event_system_init.h"
// I/O Ports initialization function
#include "ports_init.h"
// Declare your global variables here
void main(void)
{
// Declare your local variables here
unsigned char n;
// Interrupt system initialization
// Optimize for speed
#pragma optsize-
// Make sure the interrupts are disabled
#asm("cli")
// Low level interrupt: Off
// Round-robin scheduling for low level interrupt: Off
// Medium level interrupt: Off
// High level interrupt: Off
// The interrupt vectors will be placed at the start of the Application FLASH section
n=(PMIC.CTRL & (~(PMIC_RREN_bm | PMIC_IVSEL_bm | PMIC_HILVLEN_bm | PMIC_MEDLVLEN_bm | PMIC_LOLVLEN_bm)));
CCP=CCP_IOREG_gc;
PMIC.CTRL=n;
// Set the default priority for round-robin scheduling
PMIC.INTPRI=0x00;
// Restore optimization for size if needed
#pragma optsize_default
// System clocks initialization
system_clocks_init();
// Event system initialization
event_system_init();
// Ports initialization
ports_init();
// Virtual Ports initialization
vports_init();
while (1)
{
TGLBIT(PORTB.OUT,4);
}
}
运行效果打断点观察正确
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