求教关于keil编译出错的问题

只看该作者 · 2010-5-12 13:56

uchar code array_1[6]={0x40,0x1f,0xff,0xff,0x00,0x1f};
uchar code array_5[8]={0xfe,0x1f,0x44,0x1f,0x44,0x2f,0x47,0xcf};
uchar code array_9[8]={0x7c,0x0f,0x82,0x1f,0x82,0x2f,0x7f,0xcf};
uchar code array_0[8]={0x7f,0xef,0x80,0x1f,0x80,0x1f,0x7f,0xef};
uchar code array_7[8]={0x80,0x0f,0x83,0xff,0x84,0x0f,0xf8,0x0f};
uchar code array_8[8]={0x7b,0xef,0x84,0x1f,0x84,0x1f,0x7b,0xef};
uchar code array_6[8]={0x3f,0xef,0x44,0x1f,0x84,0x1f,0x03,0xef};
uchar code array_3[8]={0x40,0x2f,0x84,0x1f,0x84,0x1f,0x7b,0xef};
uchar *p[]={array_1,array_5,array_9,array_0,array_1,array_7,array_8,array_6,array_7,array_5,array_3};

void phone_no_move()
{
while(*p!='\0')
{
  no_code=*p;
  send_cmd(0x0f00|no_code);
      p++;
      }
}

我写的代码如上，定义了一个指针数组，然后编译出现“p”：not a lvalue，
p++；的地方出现这种错误，还望哪位大侠指点小弟此错啥意思，如何修改，谢谢了！
}