stm32U575 arduino进不了中断

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lulugl|

楼主 | 2022-12-14 10:58 | 只看该作者回帖奖励

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STM32, Arduino, 中断

最近在学习arduino驱动STM32U575,开发环境为vs code platformio。freertos。我在使用检测IO是可以的，但是用中断，进不了中断。代码如下：#include <Arduino.h>
#include <STM32FreeRTOS.h>
volatile bool btnPressed = true;
volatile bool btnReleased = false;
volatile int couter = 0;

SemaphoreHandle_t xSemaLED = NULL; //创建信号量Handler
volatile TickType_t btnDeounce = 0; //用于button Debounce

TickType_t timeOut = 1000; //用于获取信号量的TimeOut 1000ticks
byte pin = PB7;
void flashLED(void * pt) {

  pinMode(pin,OUTPUT);
  while(1)
  {
if(xSemaphoreTake(xSemaLED, timeOut) == pdTRUE)
{
   if((xTaskGetTickCount() - btnDeounce) < 100){
      digitalWrite(pin, !digitalRead(pin));
      vTaskDelay(1000);
   }
}
  }
}

void buttonPressed()  {
  Serial.println("but clicked.");
  btnDeounce = xTaskGetTickCountFromISR();
  xSemaphoreGiveFromISR(xSemaLED, NULL);
}
void setup() {
  Serial.begin(115200);
  Serial.println("Start flash led....");
  xSemaLED = xSemaphoreCreateBinary();
  if ( xSemaLED == NULL){
Serial.println("No Enough Ram, Unable to Create Semaphore.");
  }else{
xTaskCreate(flashLED,
            "Flash LED",
            1024,
            NULL,
            6,
            NULL);
  }
  pinMode(PC13, INPUT_PULLDOWN);
  attachInterrupt(PC13,buttonPressed,HIGH);// 创建外部中断
}

void loop() {
  // put your main code here, to run repeatedly:
}

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