#include <reg51.h>
typedef unsigned char uint8;
sbit Ir_Pin =P3^2;
uint8 Ir_Buf[4];
code uint8 a[]={0xfe,0xfc,0xfd,0xf9,0xfb,0xf3,0xf7,0xf6};//反转
code uint8 b[]={0xf6,0xf7,0xf3,0xfb,0xf9,0xfd,0xfc,0xfe};//正转
void uart_init(void)
{
TMOD = 0x01;
/* SCON = 0x50;*/
/* TH1 = 0xFD;
TL1 = 0xFD; */
/*TR1 = 1; */
}
/*
* UART发送一字节
*/
/*void UART_Send_Byte(uint8 dat)
{
SBUF = dat;
while (TI == 0);
TI = 0;
}*/
/*
* 获取低电平时间
*/
unsigned int Ir_Get_Low()
{
TL0 = 0;
TH0 = 0;
TR0 = 1;
while (Ir_Pin ==0);
TR0 = 0;
return (TH0 * 256 + TL0);
}
/*
* 获取高电平时间
*/
unsigned int Ir_Get_High()
{
TL0 = 0;
TH0 = 0;
TR0 = 1;
while (Ir_Pin ==1);
TR0 = 0;
return (TH0 * 256 + TL0);
}
void delay(unsigned int t)
{
unsigned int k;
while(t--)
{
for(k=0; k<80; k++)
{ }
}
}
main()
{
unsigned int temp;
char i,j;
uart_init();
while (1)
{
start:
while (Ir_Pin);
temp = Ir_Get_Low();
if ((temp < 7833) || (temp > 8755)) //引导脉冲低电平8500~9500us
goto start;
temp = Ir_Get_High();
if ((temp < 3686) || (temp > 4608)) //引导脉冲高电平4000~5000us
goto start;
for (i=0; i<4; i++) //4个字节
{
for (j=0; j<8; j++) //每个字节8位
{
temp = Ir_Get_Low();
if ((temp < 276) || (temp > 737)) //200~800us
goto start;
temp = Ir_Get_High();
if ((temp < 276) || (temp > 1843)) //200~2000us
goto start;
Ir_Buf[i] >>= 1;
if (temp > 1032) //1120us
Ir_Buf[i] |= 0x80;
}
}
/* UART_Send_Byte(Ir_Buf[0]);
UART_Send_Byte(Ir_Buf[1]);
UART_Send_Byte(Ir_Buf[2]);
UART_Send_Byte(Ir_Buf[3]);
*/
if(Ir_Buf[2]==0x16)//遥控器0键
{
for(i=0;i<8;i++)
{
P1=a[i];
if(i==7)
{
i=0;
}
delay(5);
if(Ir_Buf[2]==0x08)遥控器4键
break;
}
}
if(Ir_Buf[2]==0x0c)遥控器1键
{
for(i=0;i<8;i++)
{
P1=b[i];
if(i==7)
{
i=0;
}
delay(5);
if(Ir_Buf[2]==0x08)
break;
}
}
if(Ir_Buf[2]==0x08)
{
P1=0xff;
}
}
}
红外解码都没问题,我验证过了,但是比如拿下0键,正转,但是再按其他键没反应,仍然是正转,如果按下1键,反转,但是再按下其他键还是没反应,继续反转,这个和一起论坛的帖子用按键控制步进电机差不多,但是那个加入一个判断break就能实现,这个不知道为什么,求教! |